Php 从动态表单上载Codeignitor多输入文件

我有一个使用Jquery的动态表单（拖放表单），它有多个输入类型=file。因此，输入类型的名称使用随机数更改。以下是源代码视图中的示例代码：

<?php echo $error;?>
<?php echo form_open_multipart('upload/do_upload');?>
<form action="" enctype="multipart/form-data" method="post" accept-charset="utf-8">                            
<div id="sjfb-fields">

    <div class="my-3 p-3 bg-white rounded box-shadow">
            <div id="sjfb-399480" class="sjfb-field sjfb-images" style="min-height:100px;">
                <label for="images-399480" style="color:grey;font-size:12px">Upload the screenshot</label>

                <input type="file" name="img-399480" id="images-399480">
            </div>
    </div>

    <div class="my-3 p-3 bg-white rounded box-shadow">
        <div id="sjfb-857945" class="sjfb-field sjfb-images" style="min-height:100px;">
            <label for="images-857945" style="color:grey;font-size:12px">Test Images</label>
            <input type="file" name="img-857945" id="images-857945">
            </div>
    </div>
    <div class="my-3 p-3 bg-white rounded box-shadow">
        <div id="sjfb-792565" class="sjfb-field sjfb-images" style="min-height:100px;">
            <label for="images-792565" style="color:grey;font-size:12px">More Images</label>

            <input type="file" name="img-792565" id="images-792565">
           </div>
    </div>
</div>
<button type="submit" name="save" class="btn btn-primary">Save</button>
</form>

我用一个输入type=“file”尝试了上传，它可以正常工作（使用图像的名称userfile）。 此表单有多个输入类型=文件，我想知道是否有任何方法可以单独上载文件？ 我对codeigniter也是新手

谢谢

看看这个：

控制器部分：

    $files = $_FILES;  //getting the files from post
    $cpt = count($_FILES['photo']['name']); //number of files uploaded

    for($i=0;$i<$cpt;$i++){  // in loop to upload multiple files

      $file_name=$_FILES['photo']['name'][$i];

      if($i==0){     //name the file according to the number /name as u like
        echo $i;
       $name='_first';

      }elseif($i==2){

       $name='_second';  

      }else{

        $name='_third';

      }

并以html格式上传照片：输入名称更改为photo[]

<?php echo $error;?>
<?php echo form_open_multipart('upload/do_upload');?>
<form action="" enctype="multipart/form-data" method="post" accept-charset="utf-8">                            
<div id="sjfb-fields">

    <div class="my-3 p-3 bg-white rounded box-shadow">
            <div id="sjfb-399480" class="sjfb-field sjfb-images" style="min-height:100px;">
                <label for="images-399480" style="color:grey;font-size:12px">Upload the screenshot</label>

                <input type="file" name="photo[]" id="images-399480">
            </div>
    </div>

    <div class="my-3 p-3 bg-white rounded box-shadow">
        <div id="sjfb-857945" class="sjfb-field sjfb-images" style="min-height:100px;">
            <label for="images-857945" style="color:grey;font-size:12px">Test Images</label>
            <input type="file" name="photo[]" id="images-857945">
            </div>
    </div>
    <div class="my-3 p-3 bg-white rounded box-shadow">
        <div id="sjfb-792565" class="sjfb-field sjfb-images" style="min-height:100px;">
            <label for="images-792565" style="color:grey;font-size:12px">More Images</label>

            <input type="file" name="photo[]" id="images-792565">
           </div>
    </div>
</div>
<button type="submit" name="save" class="btn btn-primary">Save</button>
</form>

上传截图
测试图像
更多图片
拯救

在我的本地工作

---

有关配置选项，请参阅此链接。有关多文件上载，请参阅此链接。有关注释，请参阅hanks。从单输入多次上载type=“file”可以使用userfile[]作为名称。但是我需要使用单独的输入type=“file”进行多次上传，谢谢。如果用户没有添加第一个图像并添加第二个和第三个图像，该怎么办。I获取偏移错误U可以检查（$_FILES['photo']['name'][$I]==null）并转义它不会给出错误的部分

        $_FILES['photo']['name']= $files['photo']['name'][$i];
        $_FILES['photo']['type']= $files['photo']['type'][$i];
        $_FILES['photo']['tmp_name']= $files['photo']['tmp_name'][$i];
        $_FILES['photo']['error']= $files['photo']['error'][$i];
        $_FILES['photo']['size']= $files['photo']['size'][$i];



      $config = array(
            'file_name'     => $name,
            'allowed_types' => 'jpg',    //add option as u like
            'max_size'      => 3000,
            'overwrite'     => TRUE,
            'upload_path'=>'./uploads/'      //use your respective path to upload
      );

      $this->upload->initialize($config);
   if (!$this->upload->do_upload('photo')) {
      $data_error = array('msg' => $this->upload->display_errors());

                  } else {

                      $data = $this->upload->data();

                  }

    }

<?php echo $error;?>
<?php echo form_open_multipart('upload/do_upload');?>
<form action="" enctype="multipart/form-data" method="post" accept-charset="utf-8">                            
<div id="sjfb-fields">

    <div class="my-3 p-3 bg-white rounded box-shadow">
            <div id="sjfb-399480" class="sjfb-field sjfb-images" style="min-height:100px;">
                <label for="images-399480" style="color:grey;font-size:12px">Upload the screenshot</label>

                <input type="file" name="photo[]" id="images-399480">
            </div>
    </div>

    <div class="my-3 p-3 bg-white rounded box-shadow">
        <div id="sjfb-857945" class="sjfb-field sjfb-images" style="min-height:100px;">
            <label for="images-857945" style="color:grey;font-size:12px">Test Images</label>
            <input type="file" name="photo[]" id="images-857945">
            </div>
    </div>
    <div class="my-3 p-3 bg-white rounded box-shadow">
        <div id="sjfb-792565" class="sjfb-field sjfb-images" style="min-height:100px;">
            <label for="images-792565" style="color:grey;font-size:12px">More Images</label>

            <input type="file" name="photo[]" id="images-792565">
           </div>
    </div>
</div>
<button type="submit" name="save" class="btn btn-primary">Save</button>
</form>