最后添加到数组中的PHP将替换所有存储的数组值

我想做的是：

从数据库中获取结果

通过分配给stdClass来获取所需的值

---

将这些对象放入数组中。（您需要在

foreach

循环中实例化对象：

function get_prizes()
{
    // All prize objects are stored here
    $prizes = array();

    // Getting the prizes from a simple database table
    $query = $this->db->get('prizes');
    if ($query->num_rows() > 0) {
        foreach($query->result() as $row):

            // Prize object    
            $prize = new stdClass();

            // $prize->type = '';
            $prize->name1 = $row->prize_name;

            $prizes[] = $prize;

        endforeach;
    }

    echo json_encode($prizes);
}

---

谢谢，工作得很好。为什么它需要在内部实例化？如果数组中的值已经赋值，它如何改变数组中的值？在PHP中，对象是通过引用传递的，因此当您在循环外部创建对象时，每次迭代只会使用一个对象，并将其添加到数组中（使用不同的索引）属性

name1

将保留最后一个值，即

Toaster

；因此，您需要在每次迭代时创建一个新对象。

Item: Array ( [0] => stdClass Object ( [name1] => Radio ) ) 
Item: Array ( [0] => stdClass Object ( [name1] => Television ) [1] => stdClass Object ( [name1] => Television ) ) 
Item: Array ( [0] => stdClass Object ( [name1] => Toaster ) [1] => stdClass Object ( [name1] => Toaster ) [2] => stdClass Object ( [name1] => Toaster ) ) 
[{"name1":"Toaster"},{"name1":"Toaster"},{"name1":"Toaster"}]

function get_prizes()
{
    // All prize objects are stored here
    $prizes = array();

    // Getting the prizes from a simple database table
    $query = $this->db->get('prizes');
    if ($query->num_rows() > 0) {
        foreach($query->result() as $row):

            // Prize object    
            $prize = new stdClass();

            // $prize->type = '';
            $prize->name1 = $row->prize_name;

            $prizes[] = $prize;

        endforeach;
    }

    echo json_encode($prizes);
}