Php登录错误
当我输入用户名和密码时,就会出现这个错误 致命错误:在第32行的Z:\xampp\htdocs\zed\checklogin.php中调用未定义的函数session_register() 这是代码 main_login.phpPhp登录错误,php,Php,当我输入用户名和密码时,就会出现这个错误 致命错误:在第32行的Z:\xampp\htdocs\zed\checklogin.php中调用未定义的函数session_register() 这是代码 main_login.php <!DOCTYPE html> </html lang="en"> <head> <meta charset="utf-8"> <title>Test</title&
<!DOCTYPE html>
</html lang="en">
<head>
<meta charset="utf-8">
<title>Test</title>
</head>
</body>
<table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form name="form1" method="post" action="checklogin.php">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td colspan="3"><strong>Member Login </strong></td>
</tr>
<tr>
<td width="78">Username</td>
<td width="6">:</td>
<td width="294"><input name="myusername" type="text" id="myusername"></td>
</tr>
<tr>
<td>Password</td>
<td>:</td>
<td><input name="mypassword" type="text" id="mypassword"></td>
</tr>
<tr>
<td> </td>
<td> </td>
<td><input type="submit" name="Submit" value="Login"></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
</body>
</html>
试验
会员登录
用户名
:
密码
:
签入
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password="password"; // Mysql password
$db_name="test"; // Database name
$tbl_name="members"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// username and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];
// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);
$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);
// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword");
header("location:login_success.php");
}
else {
echo "Wrong Username or Password";
}
?>
您正在学习一个非常古老(而且很糟糕)的教程。所有mysql.*
函数都已弃用,您应该查看PDO
或MySQLi
您的错误消息:
Fatal error: Call to undefined function session_register() in Z:\xampp\htdocs\zed\checklogin.php on line 32
声明因为会话\u register()
也被弃用。您需要设置如下值:
$_SESSION['username'] = 'theusername';
session_start();
if(!isset($_SESSION['username']) || empty($_SESSION['username'])) {
die(header("Location: /login"));
}
然后,在检查用户是否已登录的页面上,应使用以下内容:
$_SESSION['username'] = 'theusername';
session_start();
if(!isset($_SESSION['username']) || empty($_SESSION['username'])) {
die(header("Location: /login"));
}
1-
2-
对于额外的cookie点,下面是一个示例PDO
query
$db = new PDO('mysql:host=localhost;dbname=testdb;charset=utf8', 'username', 'password');
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$stmt = $db->prepare("SELECT * FROM $tbl_name WHERE username=? and password=?");
$stmt->bindValue(1, $username, PDO::PARAM_STR);
$stmt->bindValue(2, $password, PDO::PARAM_STR);
if($stmt->execute()){
if($stmt->rowCount() == 1) {
$data = $stmt->fetchObject();
$_SESSION['username']
}
}
免责声明:以上是伪代码,我建议您看看PDO PHP示例。请参阅石器时代代码,确实需要使用这个有趣的结束标记。
作为开场白的具体作用是什么?或者
作为开场白?如果这确实是一个教程,你需要从你的记忆中抹去它的存在。哦,我不想你。