Php 将文本文件内爆到数据库中

我正在尝试将文本文件内爆到mysql数据库中。我有姓名、代码、邮件id、职务和薪水栏。我的密码是：

<?php
    include("includes/config.php"); 
    if ($_POST['frmSubmit']) {
        $file = $_FILES['frmUpload']['tmp_name'];           //  Get Temporary filename
        if ($file) {
            $handle = fopen($file,"r");                         //  Open the file and read
            while($strBookData = fgets($handle, 4096)) {
                $strData[] = $strBookData;
                $strData1 = str_replace(array("\r\n", "\r", "\n"), "", $strData);
                $rows = explode('\t', implode($strData1));
                $strTableColumn = count($rows);
            }
            $strDatas = array();
            foreach ($rows as $row){
                if(!empty( $row )){
                    $strDatas[] = explode('|', $row);
                }
            }
            if ($strDatas) {
                $strInsertRecords = 0;
                $strDuplicationRecords = 0;
                if ($strTableColumn == 4) {
                    for($k=1; $k<count($strDatas); $k++) { //$k=1 is initialized because $k[0] is a header field array.
                        $strStatus = doCheckDuplication($strDatas[$k]['2']);                    
                        if ($strStatus == 0) {  
                            doInsertEmployeeDetails($strDatas[$k]['0'], $strDatas[$k]['1'], $strDatas[$k]['2'], $strDatas[$k]['3'], $strDatas[$k]['4']);
                            $strInsertRecords++;            // To Get Inserted Records Count.
                        } else {
                            $strDuplicationRecords++;       // To Get Duplication Records Count.
                        }
                    }
                    if  (count($strDatas)-1 == $strInsertRecords) {
                        $strMsg = 'Employee record(s) inserted successfully!';                                                                  
                        $strClass = 'Success';
                    }
                    if  (count($strDatas)-1 != $strInsertRecords) {
                        $strMsg = 'Employee record(s) inserted successfully but some of record(s) are already exists.!';                                                                    
                        $strClass = 'Error';
                    }
                    if  (count($strDatas)-1 == $strDuplicationRecords) {
                        $strMsg = 'Employee record(s) are already exists.!';                                                                    
                        $strClass = 'Error';
                    }

                } else {
                    $strMsg = 'Column mis-match, Please verify the file.';                                                                  
                    $strClass = 'Error';
                }
            }       
        } else {
            $strMsg = 'Please upload a valid file.';                                                                    
            $strClass = 'Error';
        }
    }
?>

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但我有错误列不匹配，我不知道我缺少什么。请帮助我。

var\u dumpcount$strTableColumn；->可能不止4行？我的文本数据是：姓名|代码|邮件|名称|薪水|哈里| 100|hari@gmail.com|学员| 6000\t Syed | 101|syed@gmail.com|培训生| 6000\t拉贾| 102|raja@gmail.com|培训生| 6000\tvaru dumpcount$strTableColumn；我应用了代码var_dumpcount$strTableColumn；它以int1 int1 int1 int1 int1的形式给出输出。您的错误是：检查count$strTableColumn是否为4，但它是否为1，这样您就得到了该错误