Php 在laravel中取消设置Json并对其重新编制索引

我得到一个错误：

array_values（）要求参数1为数组，对象为给定的

下面是我的代码：

for($a=0; $a < sizeOf($participations); $a++){
    foreach($winners as $winner){
        if($winner->id == $participations[$a]->id){
            Log::info($participations);
            unset($participations[$a]);
            Log::info($participations);

        }
    }

}
$participations1 = array_values($participations);

取消设置后，我得到：

[2015-09-10 13:25:21] local.INFO: 
{"0":{"id":6,"campaignId":7,"userId":9,"created_at":"2015-09-08 16:23:48","updated_at":"2015-09-08 16:23:49","isCorrect":1},"2":{"id":8,"campaignId":7,"userId":11,"created_at":"2015-09-09 11:47:16","updated_at":"2015-09-09 11:47:16","isCorrect":1}} [] []

---

参与根本不是数组，因此，如何使用

array\u values（）

重新索引Json

这不是数组。这是JSON.ok thx~我将研究JSONuse

JSON\u decode（）

函数，将其作为数组返回。这不是数组。这是JSON.ok thx~我将研究JSONuse

JSON\u decode（）

函数，将其作为数组返回

[2015-09-10 13:25:21] local.INFO: 
{"0":{"id":6,"campaignId":7,"userId":9,"created_at":"2015-09-08 16:23:48","updated_at":"2015-09-08 16:23:49","isCorrect":1},"2":{"id":8,"campaignId":7,"userId":11,"created_at":"2015-09-09 11:47:16","updated_at":"2015-09-09 11:47:16","isCorrect":1}} [] []