Php MySQL-统计用户数量（过去30天、过去一年、所有时间）

我正在尝试进行一个查询，该查询检查clients表，并返回具有过去30天、365天和所有时间的特定值的用户计数

所有时间计数都很简单：

$stmt = $conn->prepare("SELECT count(id) AS count FROM clients WHERE referred =  :refid");
$stmt->bindParam(':refid', $refid);
$stmt->execute();
$totalreferrals = $stmt->fetchAll();

表:

id |   signup   | reffered |
----------------------------
2  | 2012-08-24 |   14     |
----------------------------
3  | 2011-10-13 |   14     |

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我不确定是否可以使用UNION组合查询，或者是否应该只进行三个不同的查询。有什么帮助吗？

也许这可以解决问题：

SELECT count(id) AS count FROM clients WHERE referred = :refid AND BETWEEN ADDDATE(NOW(), INTERVAL -1 MONTH) AND NOW();

SELECT count(id) AS count FROM clients WHERE referred = :refid AND BETWEEN ADDDATE(NOW(), INTERVAL -1 YEAR) AND NOW();

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也许这可以解决问题：

SELECT count(id) AS count FROM clients WHERE referred = :refid AND BETWEEN ADDDATE(NOW(), INTERVAL -1 MONTH) AND NOW();

SELECT count(id) AS count FROM clients WHERE referred = :refid AND BETWEEN ADDDATE(NOW(), INTERVAL -1 YEAR) AND NOW();

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我想你希望它是列的，而不是行的，如果是这样的话

SELECT  COUNT(CASE WHEN DATEDIFF(CURDATE(),signup) <= 30 THEN id
                   ELSE NULL
              END) AS Last30days ,
        COUNT(CASE WHEN DATEDIFF(CURDATE(), signup) <= 365 THEN id
                   ELSE NULL
              END) AS Last365Days ,
        COUNT(*) AS Alltime
FROM    Table1
WHERE   reffered = 14

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SELECT COUNT（CASE-WHEN-DATEDIFF（CURDATE（），signup）我想您希望它在列中，而不是在行中，如果是这样的话

SELECT  COUNT(CASE WHEN DATEDIFF(CURDATE(),signup) <= 30 THEN id
                   ELSE NULL
              END) AS Last30days ,
        COUNT(CASE WHEN DATEDIFF(CURDATE(), signup) <= 365 THEN id
                   ELSE NULL
              END) AS Last365Days ,
        COUNT(*) AS Alltime
FROM    Table1
WHERE   reffered = 14

SELECT COUNT（CASE-WHEN-DATEDIFF（CURDATE（），signup））我喜欢这个解决方案。以前从未使用过WHEN语句。我喜欢这个解决方案。以前从未使用过WHEN语句。