mysql/php更新语法，传递php变量

我有一个mysql表，列为：name，active（active是int）。我想把图片上传到服务器上，当它们已经在服务器上时，我想使它们成为活动的，以便它们被用作新的徽标。（当active=1时，pic是新徽标）我不明白为什么我的“$query”不起作用。其他一切都很好

$name = $_FILES["file"]["name"]; 
if (file_exists("/home/a1829256/public_html/admin/logo/" .$name)){          //if file already on the server
        echo "file is already on the server";
        echo ". Making it the new logo";
        $deselectlogo = "UPDATE newlogo SET active=0 WHERE active>0";               //deselect old
        $deselectlogoResult = mysql_query($deselectlogo);
        $query = ("UPDATE newlogo SET active=1 WHERE name=" .$name);            // make the new logo active
        $queryResult = mysql_query($query);
        if (!$queryResult){echo "error";}
        if ($queryResult){echo "success";}

   $query = "UPDATE newlogo SET active=1 WHERE name='".$name."'";            // make the new logo active