Php 如何将mysqli_stmt_bind_param()用于多参数?
我尝试了这个功能,它可以工作:Php 如何将mysqli_stmt_bind_param()用于多参数?,php,mysql,mysqli,Php,Mysql,Mysqli,我尝试了这个功能,它可以工作: $stmt=mysqli_stmt_init($con); if (mysqli_stmt_prepare($stmt,"INSERT INTO `files` ( `Name`) VALUES (?) ")) { // Bind parameters mysqli_stmt_bind_param($stmt,"s",$file_name); //mysqli_stmt_bind_param(
$stmt=mysqli_stmt_init($con);
if (mysqli_stmt_prepare($stmt,"INSERT INTO `files` ( `Name`) VALUES (?) "))
{
// Bind parameters
mysqli_stmt_bind_param($stmt,"s",$file_name);
//mysqli_stmt_bind_param($stmt,"s",$extension);
// Execute query
mysqli_stmt_execute($stmt);
// Bind result variables
mysqli_stmt_bind_result($stmt,$district);
// Fetch value
mysqli_stmt_fetch($stmt);
printf("%s is in files %s",$file_name,$files);
}
但如何使其适用于以下多个参数:
if (mysqli_stmt_prepare($stmt,"INSERT INTO `files` ( `FName`,`LName`) VALUES (?,?) "))
您只需要像这样扩展参数绑定:
mysqli_stmt_bind_param($stmt,"ss",$file_name,$lName);
$lName
是要插入到lName
列中的值。
type参数的第二个“s”表示$lName
变量也是一个字符串。如果不是字符串,则调整此项