Php 如果条件显示年、月、日

我是一名外行的代码编写人员，我有下面的代码正在工作

<?php
$datetime1 = new DateTime("$date_of_dissolution");
$datetime2 = new DateTime("$date_of_incorp");
$difference = $datetime1->diff($datetime2);
echo 'And the company is running: '.$difference->y.' years, '.$difference->m.' months, '.$difference->d.' days.';
?>

但是我想再添加一个条件，但是下面的代码不起作用

<?php
$datetime1 = new DateTime("$date_of_dissolution");
$datetime2 = new DateTime("$date_of_incorp");
$datetime3 = new DateTime("$date_commenced_dormancy");
$datetime4 = date("Y-m-d");

if ($active_status ==('Live but Commenced Dormancy')) {
$difference = $datetime3->diff($datetime2);
} elseif  ($active_status ==('Dissolved')) {
$difference = $datetime1->diff($datetime2);
} else {
$difference = $datetime4->diff($datetime2);

echo 'And the company is running: '.$difference->y.' years, '.$difference->m.' months, '.$difference->d.' days.';
?>

---

我应该如何修改上述代码？

如果我没有错，请忘记关闭else语句的大括号

<?php
$datetime1 = new DateTime("$date_of_dissolution");
$datetime2 = new DateTime("$date_of_incorp");
$datetime3 = new DateTime("$date_commenced_dormancy");
$datetime4 = date("Y-m-d");

if ($active_status ==('Live but Commenced Dormancy')) {
$difference = $datetime3->diff($datetime2);
} elseif  ($active_status ==('Dissolved')) {
$difference = $datetime1->diff($datetime2);
} else {
$difference = $datetime4->diff($datetime2);
}

echo 'And the company is running: '.$difference->y.' years, '.$difference->m.' months, '.$difference->d.' days.';
?>