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Php 更新产品sku和产品形象后';t更新_Php_Mysql_Sql - Fatal编程技术网

Php 更新产品sku和产品形象后';t更新

Php 更新产品sku和产品形象后';t更新,php,mysql,sql,Php,Mysql,Sql,更新产品后,sku和产品映像尚未更新。。。 但其他值也在更新 if (isset($_POST['update_product'])) { $product_id =$_POST['product_id']; $product_name =$_POST['proname']; $product_sku =$_POST['prosku']; $product_price

更新产品后,sku和产品映像尚未更新。。。 但其他值也在更新

if (isset($_POST['update_product'])) {
        $product_id           =$_POST['product_id'];
        $product_name         =$_POST['proname'];
        $product_sku          =$_POST['prosku'];
        $product_price        =$_POST['proprice'];
        $product_height       =$_POST['proheight'];
        $product_width        =$_POST['prowidth'];
        $product_weight       =$_POST['proweight'];
        $product_category     =$_POST['procategory'];
        $product_description  =$_POST['prodesc'];
        $product_image        =$_POST['product_image'];
            $sql = "UPDATE  product ". " SET product_name='$product_name', product_price='$product_price',product_sku='product_sku',product_height='$product_height', product_width='$product_width',product_weight='$product_weight',product_category='$product_category',product_image='$product_image', product_description='$product_description' "."WHERE product_id=$product_id";

    $result=mysqli_query($conn,$sql);
         if(! $result ) {
               die('Could not update data: ');
            }
            echo "Updated data successfully\n";

            mysqli_close($conn);
        }

在“product\U sku='product\U sku'”级别,您忘记了“$”,因此您将有“product\U sku='$product\U sku'”作为图像使用“$”文件['product\U image']”“

您想了解的内容。谢谢,但使用此代码后已上载产品图像。。(此处参考:)