从PHP控制器运行AJAX

很抱歉，听起来让人困惑，但我会尽可能用最好的方式解释

在控制器中，我有一个函数搜索

public function search(){
   /*
    I run my logics and get few URL from 
    where I need to fetch further data
    the urls are saved in the URL array

     $urls[0] = "http://url1.com/search1";
     $urls[1] = "http://url2.com/search2";

    I then set this in data variable and send it to view 
    so that It can be run in AJAX

    I tired running get_file_contents but it executes 
    in series one after the other URL. 
    If there are 10 URL (5 secs per URL) the over all processing time 
    increases drastically

   */

   $data["urls"] = $urls;

   $resp = $this->load->view('ajaxer',$data,TRUE);

   /* based on the $resp i need to run further business logic's */

}

现在$resp实际上只给了我HTML代码。它没有执行HTML，因此没有运行ajax

任何关于如何执行此操作的想法都将非常有用

问候,，

---

Amit

您的代码完全正常。但是您的javascript没有得到任何响应数据（只有标题），因为您没有返回任何输出

如果您想“执行您的HTML”，您需要将视图中的行更改为：

$this->load->view('ajaxer',$data);

或者这个：

$resp = $this->load->view('ajaxer',$data,TRUE);
echo $resp;

---

您忘记在控制器中回显输出。除此之外，您还需要对函数进行一些小的修改

public function search(){
    /*
     I run my logics and get few URL from
     where I need to fetch further data
     the urls are saved in the URL array

      $urls[0] = "http://url1.com/search1";
      $urls[1] = "http://url2.com/search2";

     I then set this in data variable and send it to view
     so that It can be run in AJAX

     I tired running get_file_contents but it executes
     in series one after the other URL.
     If there are 10 URL (5 secs per URL) the over all processing time
     increases drastically

    */

    // You need to check either request came from Ajax request or not. If not it will echo passed string. It prevents to access this function besides Ajax request
    if (!$this->input->is_ajax_request()) {
        echo "Ajax Requests allowed.";
        die;
    }

    $data["urls"] = $urls;

    $resp = $this->load->view('ajaxer',$data,TRUE);

    // Standard way to set response for output in json format.
    // @param status will help to check all things goes correct or not. if not please pass false on the basis or your feature's requirement
    $this->output->set_output(json_encode(array('status'=>true,'response'=>$resp)));

    // Standard way to get output set above step.
    $string = $this->output->get_output();
    echo $string;
    exit();
    /* based on the $resp i need to run further business logic's */

}

---

更新的代码在这里。希望您能找到答案

问题可能是因为您没有在ajax选项中包含

success

项。选项

success

是接收控制器输出的功能。在该函数中，您可以操作html以使用返回的数据。添加进行ajax调用的javascript代码和要更新的视图的html。@DFriend我有一个成功选项。如果成功，我将更新特定的div html。但是，div是空的，我在$resp

$resp

中得到了完整的HTML代码，其中包含HTML，因为这是

load->view（'someview'）的预期目的-返回文件“someview”中的内容（通常为html）。清楚地解释你想要达到的目标会非常有帮助。例如，您计划如何处理搜索URL？