从文本文件php mysql向多行插入数据_Php_Mysql_Web

从文本文件php mysql向多行插入数据

php mysql web

从文本文件php mysql向多行插入数据,php,mysql,web,Php,Mysql,Web,我要做的是将文本文件中的每一行插入mysql数据库的新行。我做错了什么我有一个如下所示的文本文件 11111,customer1 11112,customer2 11113,customer3 11114,customer4 <html> <head> <title>Add File To DB</title> </head> <body> <form action="list.php" method="post

我要做的是将文本文件中的每一行插入mysql数据库的新行。我做错了什么

我有一个如下所示的文本文件

11111,customer1
11112,customer2
11113,customer3
11114,customer4

<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");

    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 

    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
$sql="INSERT INTO list (number, customer) VALUES ('$_POST[number]','$_POST[customer]')";
if (!mysqli_query($con,$sql))
  {
  die('Error: ' . mysqli_error());
  }

mysqli_close($con);
}
?>
</table>
<input type="submit" value="Submit File" />
</form>
</body>
</html>

My MySQL DB包含id、number、customer字段

我的php代码不工作，如下所示

11111,customer1
11112,customer2
11113,customer3
11114,customer4

<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");

    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 

    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
$sql="INSERT INTO list (number, customer) VALUES ('$_POST[number]','$_POST[customer]')";
if (!mysqli_query($con,$sql))
  {
  die('Error: ' . mysqli_error());
  }

mysqli_close($con);
}
?>
</table>
<input type="submit" value="Submit File" />
</form>
</body>
</html>


将文件添加到数据库
您的值在数组$arrM
中，不在$\u POST
中。请试试这个：
$sql="INSERT INTO list (number, customer) VALUES ('$arrM[0]','$arrM[1]')";

您还需要确保在循环中运行此$sql
。
您的值在数组$arrM
中，而不是$\u POST
中。请试试这个：
$sql="INSERT INTO list (number, customer) VALUES ('$arrM[0]','$arrM[1]')";

您还需要确保在循环中运行此$sql
。
您的代码中存在多个问题。如果您只想从文本文件插入，可以尝试以下操作
<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");
    $arr_to_insert = array();
    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>';
       //strore text file row to an array 
       $arr_to_insert[] = $arrM;
    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
foreach($arr_to_insert as $ai){
    $sql="INSERT INTO list (number, customer) VALUES ('{$ai[0]}','{$ai[1]}')";
    if (!mysqli_query($con,$sql))
      {
      die('Error: ' . mysqli_error());
      }

}
mysqli_close($con);
}
?>
</table>
</form>
</body>
</html>


将文件添加到数据库
代码中存在多个问题。如果只想从文本文件中插入，可以尝试以下操作
<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");
    $arr_to_insert = array();
    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>';
       //strore text file row to an array 
       $arr_to_insert[] = $arrM;
    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
foreach($arr_to_insert as $ai){
    $sql="INSERT INTO list (number, customer) VALUES ('{$ai[0]}','{$ai[1]}')";
    if (!mysqli_query($con,$sql))
      {
      die('Error: ' . mysqli_error());
      }

}
mysqli_close($con);
}
?>
</table>
</form>
</body>
</html>


将文件添加到数据库
您的脚本存在多个问题
首先，您正在使用$\u POST['submit']
，但尚未在提交按钮中使用name='submit'
正如@vinod所说，您的值在数组中$arrM不在$\u POST`

现在您需要在循环中插入数据。确保只包含一次连接，并在所有数据库操作完成后关闭连接
<html>
 <head>
  <title>Add File To DB</title>
 </head>

 <body>
  <form action="list.php" method="post">
  <input type="submit" name='submit' value="Submit File" /> <!-- Provide name `submit` to your button so that you can access $_POST['submit'] -->
  <table>

  <?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");

    //include your connection around here so it is included only once
    include "connection.php";

    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 
       if (isset($_POST['submit'])) {               
            $sql = "INSERT INTO list (number, customer) VALUES ('$arrM[0]','$arrM[0]')"; //here should be $arrM
            if (!mysqli_query($con,$sql)) {
              die('Error: ' . mysqli_error());
            }               
        }
    }

    fclose($f);
    mysqli_close($con); //close your database connection here
  ?>
 </table>
 <!--<input type="submit" value="Submit File" />-->
 </form>
 </body>
</html>


将文件添加到数据库
您的脚本存在多个问题
首先，您正在使用$\u POST['submit']
，但尚未在提交按钮中使用name='submit'
正如@vinod所说，您的值在数组中$arrM不在$\u POST`

现在您需要在循环中插入数据。确保只包含一次连接，并在所有数据库操作完成后关闭连接
<html>
 <head>
  <title>Add File To DB</title>
 </head>

 <body>
  <form action="list.php" method="post">
  <input type="submit" name='submit' value="Submit File" /> <!-- Provide name `submit` to your button so that you can access $_POST['submit'] -->
  <table>

  <?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");

    //include your connection around here so it is included only once
    include "connection.php";

    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 
       if (isset($_POST['submit'])) {               
            $sql = "INSERT INTO list (number, customer) VALUES ('$arrM[0]','$arrM[0]')"; //here should be $arrM
            if (!mysqli_query($con,$sql)) {
              die('Error: ' . mysqli_error());
            }               
        }
    }

    fclose($f);
    mysqli_close($con); //close your database connection here
  ?>
 </table>
 <!--<input type="submit" value="Submit File" />-->
 </form>
 </body>
</html>


将文件添加到数据库
如果要将文本文件的数据插入数据库，则可以执行此操作。
如果要将文本文件的数据插入数据库，则可以执行此操作。
您必须正确插入值
$sql="INSERT INTO list (number, customer) VALUES ('".$arrM[0]."','".$arrM[1]."')"; 

您必须正确插入值
$sql="INSERT INTO list (number, customer) VALUES ('".$arrM[0]."','".$arrM[1]."')"; 

$arrM
在$sql=
行中不可见$arrM
在$sql=
行中不可见更正刚刚学习。如果我想要一个在底部，一个在顶部，我可以这样做吗？或者to按钮会相互冲突吗？您可以有多个submit。这不会产生冲突，两者都会起作用。正确的做法就是学习。如果我想要一个在底部，一个在顶部，我可以这样做吗？或者to按钮会相互冲突吗？您可以有多个submit。这不会产生冲突，两者都会起作用。