Php symfony获取所选的choiceType值

Php symfony获取所选的choiceType值,php,symfony,symfony-3.3,Php,Symfony,Symfony 3.3,嗨,我在做symfony 3.3项目。我有一个带有choiceType的表单,我想知道阅读所选选项的正确方法是什么 控制器代码 $form = $this->createFormBuilder() ->add('decision', ChoiceType::class, array('choices' => array( 'valider' => 'valider', 'rejeter' => 'rejeter',

嗨,我在做symfony 3.3项目。我有一个带有choiceType的表单,我想知道阅读所选选项的正确方法是什么

控制器代码

$form = $this->createFormBuilder()
        ->add('decision', ChoiceType::class, array('choices'  => array(
        'valider' => 'valider',
        'rejeter' => 'rejeter',
    )

    ))
        ->setAction($this->generateUrl('validerRejeter', array('id' => $cours->getId())))
        ->setMethod('POST')
        ->getForm();

  $form->handleRequest($request); 
  if ($form->isSubmitted() && $form->isValid())
  {
    $choix=$request->request->get('form');
    if ($choix == 'valider')
        $cours->setEtat('publié');
    else 
        $em->remove($cours);
        $em->flush();
    }

$choix = $form->get('decision')->getData();
$choix = $request->request->get('decision');