PHP/MySQL代码赢得';t在表中插入用户ID和密码
我正在处理一个任务,似乎无法让我的代码将userid和密码插入到我的“users”表中。输入名称是“userid”和“password”-我还使用了一个哈希密码示例。为了简洁起见,我省略了if($result==false)后面的代码。如果您没有看到任何错误,那么我将把它记为SQL表/主机设置中的错误PHP/MySQL代码赢得';t在表中插入用户ID和密码,php,mysql,login,sessionid,login-script,Php,Mysql,Login,Sessionid,Login Script,我正在处理一个任务,似乎无法让我的代码将userid和密码插入到我的“users”表中。输入名称是“userid”和“password”-我还使用了一个哈希密码示例。为了简洁起见,我省略了if($result==false)后面的代码。如果您没有看到任何错误,那么我将把它记为SQL表/主机设置中的错误 Thanks so much. <?php $userid = $_POST['userid']; $password = $_POST['password'];
Thanks so much.
<?php
$userid = $_POST['userid'];
$password = $_POST['password'];
require('constants.php');
include_once('menu.php');
//starts connection
$dbc = mysqli_connect(HOST,USERID,PASSWORD,DB);
if(isset($_POST['register'])) {
$query = "INSERT INTO `users` (`userid`, `password`) VALUES (?,?)";
// PREPARED STATEMENTS
$stmt = mysqli_prepare($dbc,$query);
include('PasswordHash.php');
$pwdHasher = new PasswordHash(8, false);
$hash = $pwdHasher->HashPassword($password);
mysqli_stmt_bind_param($stmt,'ss',$userid,$hash);
// execute query
$result = mysqli_stmt_execute($stmt);
else {
//user successfully signed in
//session the session value to the user id
$_SESSION['uid']=$userid;
//display the page
include('displayChat.php');
}
}
?>
非常感谢。
我建议从mysqli_*转到PDO
我并不真的使用mysqli,但这应该可以用。如果没有,请发布您正在使用的所有代码以使其更容易。
您的else{
require 'constants.php';
include_once 'menu.php';
if( isset($_POST['register']) )
{
$dbc = mysqli_connect(HOST,USERID,PASSWORD,DB);
$stmt = mysqli_prepare( $dbc, "INSERT INTO users (userid, password) VALUES ( :userid, :password )" );
$stmt = mysqli_execute(':userid' =>$_POST['userid'], ':password' => $_POST['password']);
include('PasswordHash.php');
$pwdHasher = new PasswordHash(8, false);
$hash = $pwdHasher->HashPassword($_POST['password']);
mysqli_stmt_bind_param($stmt,'ss',$_POST['userid'],$hash);
$result = mysqli_stmt_execute($stmt);
} else {
$_SESSION['uid']= $userid;
include_once 'displayChat.php';
}
您是否尝试过使用
mysqli\u error()
?