如何在PHP中按键的值对关联数组进行排序
很难解释,下面是一个例子:如何在PHP中按键的值对关联数组进行排序,php,arrays,Php,Arrays,很难解释,下面是一个例子: $strings = array( array("languageCode" => "ES", "string" => "hola"), array("languageCode" => "EN", "string" => "hello"), array("languageCode" => "IT", "string" => "ciao"), array("languageCode" => "CHS
$strings = array(
array("languageCode" => "ES", "string" => "hola"),
array("languageCode" => "EN", "string" => "hello"),
array("languageCode" => "IT", "string" => "ciao"),
array("languageCode" => "CHS", "string" => "您好"),
);
我想通过定义顺序,按languageCode
value对字符串进行排序:
function magicStringOrder(array $strings, array $languageCodeOrder){
// ....
return $strings;
}
$strings = magicStringOrder($strings, array('EN', 'IT') );
$strings = array(
array("languageCode" => "EN", "string" => "hello"),
array("languageCode" => "IT", "string" => "ciao"),
array("languageCode" => "ES", "string" => "hola"),
array("languageCode" => "CHS", "string" => "您好"),
);
有magicStringOrder
我现在知道,这是一个简单的问题,解决几个循环。我需要一个非常快速的函数(它被多次调用,使用大数组)如果给一种语言赋予权重不是问题,那么排序会变得更容易,因此也会更快 您可以使用
asort
根据$languageCodeOrder
存储的权重对数组进行排序。如果一种语言在$languageCodeOrder
中不存在,它的权重将变为0,并移到有序数组的末尾
阵列的最终顺序将从高重量到低重量。也就是说:如果EN的权重为1,它将出现在具有2的数组之后
$strings = array(
array("languageCode" => "ES", "string" => "hola"),
array("languageCode" => "EN", "string" => "hello"),
array("languageCode" => "IT", "string" => "ciao"),
array("languageCode" => "CHS", "string" => "您好"),
);
function magicStringOrder(array $strings, array $languageCodeOrder) {
uasort($strings, function($a,$b) use ($languageCodeOrder) {
$val_a = (isset($languageCodeOrder[$a["languageCode"]])) ? $languageCodeOrder[$a["languageCode"]] : 0;
$val_b = (isset($languageCodeOrder[$b["languageCode"]])) ? $languageCodeOrder[$b["languageCode"]] : 0;
return $val_b - $val_a;
});
return $strings;
}
$strings_ordered = magicStringOrder($strings, array('EN' => 1, 'IT' => 2, 'ES' => 3, 'CHS' => 4));
print_r($strings_ordered);
如果数组很大,那么最好依靠PHP排序算法,而不是尝试实现自定义算法
可以随意修改算法中的任何内容(顺序或任何内容)。不使用php排序函数的另一个想法:
// sort by cmp $arr[$magic_key] <-> arr $magic_order
function magicSort($arr, $magic_key="", $magic_order = array())
{
$sorted = array();
foreach($magic_order AS $v) {
foreach($arr AS $k2 => $v2) {
if($v===$v2[$magic_key]) {
$sorted[] = $v2;
unset($arr[$k2]);
}
}
}
// attach what's left
return array_merge($sorted, $arr);
}
输出至:
$magic_order
也可以为空。如果是这样的话,数组将被重新索引。带有值的数组,不存在于$magic_顺序中
将下移并保持其顺序
不确定,如果这正是您所需要的。您对语言中没有条目的值的期望值是多少?@MarkBaker如果定义的顺序采用该位置,否则保持其位置该函数与我的类似(请参见我的编辑)。然而,我希望秩序中不存在语言,保持它们的地位。如果可能,最好根据新位置(0,1,2)和(1,2,4)重新计算指数。非常感谢,非常简单,很高兴您喜欢@SimoneNigro:)
$strings = array(
array("languageCode" => "ES", "string" => "hola"),
array("languageCode" => "EN", "string" => "hello"),
array("languageCode" => "IT", "string" => "ciao"),
array("languageCode" => "CHS", "string" => "??"),
);
print_r(magicSort($strings, "languageCode", array("EN", "IT")));
Array
(
[0] => Array
(
[languageCode] => EN
[string] => hello
)
[1] => Array
(
[languageCode] => IT
[string] => ciao
)
[2] => Array
(
[languageCode] => ES
[string] => hola
)
[3] => Array
(
[languageCode] => CHS
[string] => 您好
)
)