Php 按日过滤

我试图只显示今天结果的信息。 下面的示例显示了24小时内的信息

我只需要显示当天的信息

示例：

$sql = "SELECT COUNT(*) as c 
        FROM toutcome 
        WHERE AffID = '$affID' AND 
        CompletedDate > DATE_SUB(CURDATE(), INTERVAL 1 DAY) ";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
echo  $row['c'] ; 

我也尝试过

$sql = "SELECT COUNT(*) as c 
        FROM toutcome 
        WHERE AffID = '$affID' AND 
        CompletedDate > DATE_SUB(CURDATE(), INTERVAL 24 HOUR) ";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
echo  $row['c'] ; 

试试这个

SELECT COUNT(*)
 as c FROM toutcome 
WHERE AffID = '$affID' 
AND 
TIMESTAMPDIFF(
    DAY,
    DATE(CompletedDate),
    DATE(CURRENT_TIMESTAMP)
) = 1

尝试：

如果您知道

CompletedDate

将永远不会在未来出现，那么：

SELECT COUNT(*) as c FROM toutcome WHERE AffID = '$affID' AND CompletedDate >= CURDATE()

---

Arun的解决方案不会在

CompletedDate

CompletedDate>=CURDATE（）上使用索引

SELECT COUNT(*) as c FROM toutcome WHERE AffID = '$affID' AND CompletedDate >= CURDATE()