Php MYSQL的库存管理设计
我不知道数据库的设计是否是错误的，或者我解决问题的方法是否是错误的，但我正在使用inventory/php/mysql软件 假设我有这张桌子作为库存Php MYSQL的库存管理设计,php,mysql,Php,Mysql,我不知道数据库的设计是否是错误的，或者我解决问题的方法是否是错误的，但我正在使用inventory/php/mysql软件 假设我有这张桌子作为库存 | auto_inc | id_pro | name | qty | unit_price | | | | | | | | 1 | PA1 | Paper | 10 | 100 | | 2 | PA
| auto_inc | id_pro | name | qty | unit_price |
| | | | | |
| 1 | PA1 | Paper | 10 | 100 |
| 2 | PA1 | Paper | 10 | 200 |
| 3 | FO1 | Folder | 6 | 300 |
| 4 | FO1 | Folder | 6 | 400 |
| auto_inc | where_to | id_pro | name | qty | cost |
| | | | | | |
| 1 | RGUA | CF1 | Paper | 12 | ??? |
| 2 | SANV | PA1 | Folder | 7 | ??? |
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "inventory_db";
//connection to the database
$mysqli = mysqli_connect($hostname, $username, $password, $db);
//Input variables
$code = "PA1";
$name = "Paper";
$qtyreq = 12;
$where_to = "ABCD";
//Output variables
$totalcost = 0;
$qtyout = 0;
if ($result = $mysqli->query("SELECT `auto_inc`, `id_pro`, `name`, `qty`, `unit_price` FROM `inventory` where `id_pro` = '$code' order by unit_price asc"))
{
while ($row = mysqli_fetch_assoc($result))
{
if($qtyreq > 0)
{
$batchout = 0;
$rem = max($row['qty']-$qtyreq,0);
if($rem == 0)
$batchout = $row['qty']; //This means there are no items of this cost remaining
else
$batchout = $qtyreq; //This means there are items remaining and therefore our next loop (within the while) will check for the next expensive item
$totalcost += ($batchout * $row['unit_price']);
$qtyreq -= $batchout;
$qtyout += $batchout;
$sql = "Update inventory set qty = (qty - $batchout) where auto_inc = ".$row["auto_inc"];
echo $sql."</br>";
$mysqli->query($sql);
}
}
$sql = "Insert into shipments (`where_to`, `id_pro`, `name`, `qty`, `cost`) values ('$where_to','$code','$name',$qtyout,$totalcost)";
echo $sql;
$mysqli->query($sql);
$result->free();
}
$mysqli->close();
?>
我试图在这里实现fifo方法，但我不知道如何实现它通过更新查询，您的问题很容易解决，但我想这并不能回答您的问题
UPDATE inventory SET qty = 0 WHERE auto_inc = 1;
UPDATE inventory SET qty = 8 WHERE auto_inc = 2;
UPDATE shipments SET cost = 1400 WHERE auto_inc = 1;
根据您的业务逻辑，这可能是一个相当复杂的系统：-）您的问题很容易解决，只需更新查询，但我想这并不能回答您的问题
UPDATE inventory SET qty = 0 WHERE auto_inc = 1;
UPDATE inventory SET qty = 8 WHERE auto_inc = 2;
UPDATE shipments SET cost = 1400 WHERE auto_inc = 1;
根据您的业务逻辑，这可能是一个相当复杂的系统：-）解决方案：
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "inventory_db";
//connection to the database
$mysqli = mysqli_connect($hostname, $username, $password, $db);
//Input variables
$code = "PA1";
$name = "Paper";
$qtyreq = 12;
$where_to = "ABCD";
//Output variables
$totalcost = 0;
$qtyout = 0;
if ($result = $mysqli->query("SELECT `auto_inc`, `id_pro`, `name`, `qty`, `unit_price` FROM `inventory` where `id_pro` = '$code' order by unit_price asc"))
{
while ($row = mysqli_fetch_assoc($result))
{
if($qtyreq > 0)
{
$batchout = 0;
$rem = max($row['qty']-$qtyreq,0);
if($rem == 0)
$batchout = $row['qty']; //This means there are no items of this cost remaining
else
$batchout = $qtyreq; //This means there are items remaining and therefore our next loop (within the while) will check for the next expensive item
$totalcost += ($batchout * $row['unit_price']);
$qtyreq -= $batchout;
$qtyout += $batchout;
$sql = "Update inventory set qty = (qty - $batchout) where auto_inc = ".$row["auto_inc"];
echo $sql."</br>";
$mysqli->query($sql);
}
}
$sql = "Insert into shipments (`where_to`, `id_pro`, `name`, `qty`, `cost`) values ('$where_to','$code','$name',$qtyout,$totalcost)";
echo $sql;
$mysqli->query($sql);
$result->free();
}
$mysqli->close();
?>
解决方案：
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "inventory_db";
//connection to the database
$mysqli = mysqli_connect($hostname, $username, $password, $db);
//Input variables
$code = "PA1";
$name = "Paper";
$qtyreq = 12;
$where_to = "ABCD";
//Output variables
$totalcost = 0;
$qtyout = 0;
if ($result = $mysqli->query("SELECT `auto_inc`, `id_pro`, `name`, `qty`, `unit_price` FROM `inventory` where `id_pro` = '$code' order by unit_price asc"))
{
while ($row = mysqli_fetch_assoc($result))
{
if($qtyreq > 0)
{
$batchout = 0;
$rem = max($row['qty']-$qtyreq,0);
if($rem == 0)
$batchout = $row['qty']; //This means there are no items of this cost remaining
else
$batchout = $qtyreq; //This means there are items remaining and therefore our next loop (within the while) will check for the next expensive item
$totalcost += ($batchout * $row['unit_price']);
$qtyreq -= $batchout;
$qtyout += $batchout;
$sql = "Update inventory set qty = (qty - $batchout) where auto_inc = ".$row["auto_inc"];
echo $sql."</br>";
$mysqli->query($sql);
}
}
$sql = "Insert into shipments (`where_to`, `id_pro`, `name`, `qty`, `cost`) values ('$where_to','$code','$name',$qtyout,$totalcost)";
echo $sql;
$mysqli->query($sql);
$result->free();
}
$mysqli->close();
?>
谢谢你的投入，这对我来说真的很复杂：谢谢你的投入，这对我来说真的很复杂：很高兴，如果你有任何问题，请告诉我。它工作得很好！如果可以的话，我还有两个问题。如果我想装运多个产品，我想我必须添加一个装运id来对装运进行分组，但我不知道怎么做。使用此结构，可以取消发货并将产品返回库存，否则我必须更改方法。如果您希望能够在同一“发货”中“发货”多个产品，则需要稍微重新设计表格。“产品”的取消也需要一点重组，因此，如果客户返回6个PA1，例如，您的数据库设计需要知道它来自库存
中的id
，以便在取消/返回后可以将其重新分配到正确的库存
条目。因此，我将再添加一个表，即orders
。通过将orders
中的id
链接到order\u id
中的order\u id
查看要分配给shippings
的订单作为装运包，非常荣幸，如果您有任何问题，请告诉我。它工作得非常好！如果可以的话，我还有两个问题。如果我想装运多个产品，我想我必须添加一个装运id来对装运进行分组，但我不知道怎么做。使用此结构，可以取消发货并将产品返回库存，否则我必须更改方法。如果您希望能够在同一“发货”中“发货”多个产品，则需要稍微重新设计表格。“产品”的取消也需要一点重组，因此，如果客户返回6个PA1，例如，您的数据库设计需要知道它来自库存
中的id
，以便在取消/返回后可以将其重新分配到正确的库存
条目。因此，我将再添加一个表，即orders
。通过将orders
中的id
链接到shippings中的order\u id
来查看要分配给shippings
的订单即发货包