Php 遍历未知的json键

我不知道如何像这样解析遍历数组数据

{
  "foo-1": [
    [
      A,
      3
    ],
    [
      B,
      3
    ]
  ],
  "foo-2": [
    [
      A,
      1
    ],
    [
      B,
      7
    ]
  ],
  "foo-3": [
    [
      A,
      1
    ],
    [
      B,
      6
    ]
  ]
}

(foo-1,foo-2,foo-3)
(A,B)
(3,3)(1,7)(1,6)

我想要这样的结果

{
  "foo-1": [
    [
      A,
      3
    ],
    [
      B,
      3
    ]
  ],
  "foo-2": [
    [
      A,
      1
    ],
    [
      B,
      7
    ]
  ],
  "foo-3": [
    [
      A,
      1
    ],
    [
      B,
      6
    ]
  ]
}

(foo-1,foo-2,foo-3)
(A,B)
(3,3)(1,7)(1,6)

我的代码

$data = file_get_contents("example/data");
$parsing = json_decode($data, true);

foreach($parsing as $row=>$val){
   $data1 .= $row; //success

   foreach($row as $rows){ // don't know how to parsing child data
    $data2 .= $rows[0];
    $data3 .= $rows[1];
    }
}

---

试一试，如果这是你想要的，请告诉我：

//$arrays = array("foo-1" => array(array("A", 3), array("B", 3)), "foo-2" => array(array("A", 1), array("B", 7)), "foo-3" => array(array("A", 1), array("B", 6)));

$data = file_get_contents("example/data"); // enter your link here
$arrays = json_decode($data, true);

$names = "(";
$letters = "(";
$numbers = "";
$coordinate = "";

foreach($arrays as $arrayName => $array) {
    if(array_search($arrayName, array_keys($arrays)) == 0) {
        $names .= $arrayName;
    }else{
        $names .= ",".$arrayName;
    }
    foreach($array as $key => $nestedArray) {
        foreach($nestedArray as $letterOrNum => $value) {
            if($letterOrNum == 0) { // it's a letter
                if($key + 1 == 1) {
                    $nextLetter = $array[$key + 1][0];
                    if (!strpos($letters, $value.','.$nextLetter) !== false) {
                        if($key == 0 && array_search($arrayName, array_keys($arrays)) == 0) {
                            $letters .= $value;
                        }else{
                        $letters .= ",".$value;
                        }
                    }
                }else{
                    $previousLetter = $array[$key - 1][0];
                    if (!strpos($letters, $previousLetter.','.$value) !== false) {
                        if($key == 0 && array_search($arrayName, array_keys($arrays)) == 0) {
                            $letters .= $value;
                        }else{
                        $letters .= ",".$value;
                        }
                    }
                }
            }else{ // its a number
                if($key == 0) {
                    $coordinate .= "(".$value.",";
                }else{
                    $coordinate .= $value.")";
                }
                $numbers .= $coordinate;
                $coordinate = "";
            }
        }
    }
}

$names .= ")";
$letters .= ")";

echo $names;
echo $letters;
echo $numbers;

---

演示：

这是否回答了您的问题？不，先生，不同之处我不理解这个问题。我想解析foo-1、foo-2、foo-3和所有子数据的动态数据，请尝试我的代码，看起来很简单，但我不知道如何做抱歉，先生，标记foo-1、foo-2，foo-3它的动态可以用其他名称更改非常感谢@Codesee我坚持了3天code@fitra因为您的数组是动态的，所以我对我的答案做了一些更改