Php google maps js v3 xml为空
当我运行XML时,我试图检索XML并将其放入var标记中Php google maps js v3 xml为空,php,javascript,mysql,xml,google-maps-api-3,Php,Javascript,Mysql,Xml,Google Maps Api 3,当我运行XML时,我试图检索XML并将其放入var标记中 var markers = xml.documentElement.getElementsByTagName("marker"); 我得到一个错误,说XML为null,这是我在运行生成XML的文件时得到的XML This XML file does not appear to have any style information associated with it. The document tree is shown below.
var markers = xml.documentElement.getElementsByTagName("marker");
我得到一个错误,说XML为null,这是我在运行生成XML的文件时得到的XML
This XML file does not appear to have any style information associated with it. The document tree is shown below.
<markers>
<marker name="funtimes" address="5451 Forest Cove Lane" lat="34.1519" lng="-118.774717" type="Basketball" desc="going to play fun times with fun people" date="2012-12-29" time="23:00:00" eventcap="4" eventcur="10" eventid="1" admin="true"/>
<marker name="Event test" address="1231 fake st" lat="34.1517" lng="-118.77234" type="Cycling" desc="just a description" date="2013-01-31" time="12:00:00" eventcap="10" eventcur="4" eventid="2" admin="true"/>
<marker name="Event test 2" address="1231 fake st" lat="34.1512" lng="-118.77421" type="Football" desc="just a description 2" date="2013-01-31" time="12:00:00" eventcap="10" eventcur="3" eventid="3" admin="true"/>
<marker name="funtimes" address="5451 Forest Cove Lane" lat="34.1519" lng="-118.774717" type="Basketball" desc="going to play fun times with fun people" date="2012-12-29" time="23:00:00" eventcap="4" eventcur="10" eventid="1" admin="false"/>
<marker name="Event test" address="1231 fake st" lat="34.1517" lng="-118.77234" type="Cycling" desc="just a description" date="2013-01-31" time="12:00:00" eventcap="10" eventcur="4" eventid="2" admin="false"/>
<marker name="Event test 2" address="1231 fake st" lat="34.1512" lng="-118.77421" type="Football" desc="just a description 2" date="2013-01-31" time="12:00:00" eventcap="10" eventcur="3" eventid="3" admin="false"/>
<marker name="Event test 3" address="2142 fake st" lat="34.1602" lng="-118.77789" type="Football" desc="just a description 3" date="2013-01-28" time="13:00:00" eventcap="8" eventcur="2" eventid="4" admin="false"/>
</markers>
我已使用生成的XML从运行您的代码,没有错误。如果在我的文件中删除了行标题(“内容类型:text/xml”)
,我会得到错误未捕获类型错误:无法读取null的属性“documentElement”
,这表明您没有发送标题。记住,在发送任何实际输出之前,必须调用header(),可以是通过普通HTML标记、文件中的空行,也可以是通过PHP
试一试
他的问题是缺少标题(“内容类型:text/xml”);我的文件中有这样一个文件,它使xml成为可能的副本。你能在浏览器中打开xml吗?你在哪个浏览器中发现这个错误?我可以在firefox中打开xml,我在最初的问题中公布了结果。错误也出现在firefox中
downloadUrl("mapXML2.php", function(data) {
var xml = data.responseXML;
var markers = xml.documentElement.getElementsByTagName("marker");
function downloadUrl(url, callback) {
var request = window.ActiveXObject ?
new ActiveXObject('Microsoft.XMLHTTP') :
new XMLHttpRequest;
request.onreadystatechange = function() {
if (request.readyState == 4) {
request.onreadystatechange = doNothing;
callback(request, request.status);
}
};
request.open('GET', url, true);
request.send(null);
}
header("Content-type: text/xml");
// Start XML file, create parent node
$dom = new DOMDocument("1.0");
$node = $dom->createElement("markers");
$parnode = $dom->appendChild($node);
//Connect to database