Php 如何根据yii2中的登录用户进行更新、查看、删除？

我必须根据登录用户更改查看、更新、删除的id，但当我单击查看时，我会获得索引id。我想根据id更改特定公司。请帮助我我是yii2的新手…提前感谢。 actionIndex（）

index.php

    <?= GridView::widget([
            'dataProvider' => $dataProvider,
            'dataProvider' => $dataProvider1,
            'filterModel' => $searchModel,
            'columns' => [
            'ven_id',
            'ven_company_name',
            'ven_website',
             'ven_contact_no',
             'ven_email_id:email',
          ['class' => 'yii\grid\ActionColumn',
              'header' => 'Action',
              'template' => '{view} {edit} {delete}',
              'buttons' => [
                 'view' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url);
                 },
                 'edit' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-pencil"></span>', $url);
                 },
                 'delete' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-trash"></span>', $url);
                 },
              ],
              'urlCreator' => function ($action, $dataProvider, $key, $index) {

                if ($action === 'view') {
                     return Url::to(['vendors/view', 'id' =>$dataProvider['ven_id']]);
                }
                if ($action === 'edit') {
                    return Url::to(['/vendors/update', 'id' =>$dataProvider['ven_id']]);
                }
                if ($action === 'delete') {
                   return Url::to(['/vendors/delete', 'id' =>$dataProvider['ven_id']]);
                }                    
                return $url;
            }
          ],
      ],
]); ?>

很抱歉添加了“答案”（无法添加评论，需要声誉>=50）

能否添加索引视图渲染文件

在我看来，这将是该文件中的一个错误，例如，适用于我的方法：

GridView::widget([
    'dataProvider' => $dataProvider,
    'filterModel' => $searchModel,
    'columns' => [
        'name',
        ['class' => 'yii\grid\ActionColumn',
            'header' => 'Action',
            'template' => '{view} {edit} {delete}',
            'buttons' => [
               'view' => function ($url, $model) {
                 return Html::a('View', $url);
               },
               'edit' => function ($url, $model) {
                 return Html::a('Edit', $url);
               },
               'delete' => function ($url, $model) {
                 return Html::a('Delete', $url);
               },
            ],
        ],
    ],
]);

对于图标和型号->id，我想您需要这个

   GridView::widget([
      'dataProvider' => $dataProvider,
      'filterModel' => $searchModel,
      'columns' => [
          'name',
          ['class' => 'yii\grid\ActionColumn',
              'header' => 'Action',
              'template' => '{view} {edit} {delete}',
              'buttons' => [
                 'view' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url);
                 },
                 'edit' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-pencil"></span>', $url);
                 },
                 'delete' => function ($url, $model) {
                    return Html::a('<span class="glyphicon glyphicon-trash"></span>', $url,[
                    'title' => Yii::t('yii', 'Delete'),
                    'data-confirm' => Yii::t('yii', 'Are you sure you want to delete this item?'),
                    'data-method' => 'post',
                ]);
                 },
              ],
              'urlCreator' => function ($action, $model, $key, $index) {

                if ($action === 'view') {
                    $url = Url::to(['/yourController/view', 'id' =>$model->id]);
                }
                if ($action === 'edit') {
                    $url = Url::to(['/yourController/edit', 'id' =>$model->id]);
                }
                if ($action === 'delete') {
                    $url = Url::to(['/yourController/delete', 'id' =>$model->id]);
                }                    
                return $url;
            }
          ],
      ],
  ]);

GridView:：widget([
“dataProvider”=>$dataProvider，
“filterModel”=>$searchModel，
“列”=>[
“姓名”，
['class'=>'yii\grid\ActionColumn'，
'标题'=>'操作'，
'模板'=>'{view}{edit}{delete}'，
“按钮”=>[
“查看”=>函数（$url$model）{
返回Html:：a（“”，$url）；
},
“编辑”=>函数（$url$model）{
返回Html:：a（“”，$url）；
},
'delete'=>函数（$url$model）{
返回Html:：a（“”，$url[
'title'=>Yii:：t（'Yii'，'Delete'），
'数据确认'=>Yii:：t（'Yii'，'您确定要删除此项目吗？'），
“数据方法”=>“post”，
]);
},
],
“urlCreator”=>函数（$action、$model、$key、$index）{
如果（$action=='view'）{
$url=url:：to（['/yourController/view'，id'=>$model->id]）；
}
如果（$action=='edit'）{
$url=url:：to（['/yourController/edit'，id'=>$model->id]）；
}
如果（$action=='delete'）{
$url=url:：to（['/yourController/delete'，id'=>$model->id]）；
}                    
返回$url；
}
],
],
]);
I have update my code你能告诉我我哪里错了吗使用你的代码视图、更新、删除按钮集而不是视图、更新、删除的图像试图获取非对象的属性在调用url$url=url:：to（['/yourController/view'，id'=>$model->id]）后出现此错误；你能解释一下这一行吗？因为url不调用可能是id传递错误，因为PK表中的id是ven_IDB，但当我点击删除它时，这里有一个问题，给出错误方法不允许。此url只能处理以下请求方法：POST。添加此错误后，请给出我的错误建议。我在此行“数据”=>[“确认”=>“是否确实要删除此活动？”，“方法”=>“POST”，]）；是语法错误，意外“=>”（T_双箭头）
   GridView::widget([
      'dataProvider' => $dataProvider,
      'filterModel' => $searchModel,
      'columns' => [
          'name',
          ['class' => 'yii\grid\ActionColumn',
              'header' => 'Action',
              'template' => '{view} {edit} {delete}',
              'buttons' => [
                 'view' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url);
                 },
                 'edit' => function ($url, $model) {
                   return Html::a('<span class="glyphicon glyphicon-pencil"></span>', $url);
                 },
                 'delete' => function ($url, $model) {
                    return Html::a('<span class="glyphicon glyphicon-trash"></span>', $url,[
                    'title' => Yii::t('yii', 'Delete'),
                    'data-confirm' => Yii::t('yii', 'Are you sure you want to delete this item?'),
                    'data-method' => 'post',
                ]);
                 },
              ],
              'urlCreator' => function ($action, $model, $key, $index) {

                if ($action === 'view') {
                    $url = Url::to(['/yourController/view', 'id' =>$model->id]);
                }
                if ($action === 'edit') {
                    $url = Url::to(['/yourController/edit', 'id' =>$model->id]);
                }
                if ($action === 'delete') {
                    $url = Url::to(['/yourController/delete', 'id' =>$model->id]);
                }                    
                return $url;
            }
          ],
      ],
  ]);