PHP SQL Server-动态表行和列?
我有一个和我之前的问题相似的问题- 在该查询中,我知道将调用行标题,并且只需要动态创建列标题。但是现在,我也不知道行标题 所以我有一个疑问PHP SQL Server-动态表行和列?,php,sql-server-2008,pivot,Php,Sql Server 2008,Pivot,我有一个和我之前的问题相似的问题- 在该查询中,我知道将调用行标题,并且只需要动态创建列标题。但是现在,我也不知道行标题 所以我有一个疑问 select eng, count, weekof from dbo.RPT_ENG_WEEK ('2013-03-03', '2013-03-16', '2013-03-03', '2013-03-16') order by eng, weekof asc 返回以下数据: eng count weekof James 11 20
select eng, count, weekof from dbo.RPT_ENG_WEEK ('2013-03-03', '2013-03-16', '2013-03-03', '2013-03-16') order by eng, weekof asc
返回以下数据:
eng count weekof
James 11 2013-03-03
James 12 2013-03-10
Bill 2 2013-03-03
Gary 15 2013-03-03
Gary 5 2013-03-10
Fred 3 2013-03-03
Fred 2 2013-03-10
所以我想把它变成一行一行,一周一列,如下所示
week: 2013-03-03 2013-03-10
James: 11 12
Bill: 2 0
Gary: 15 5
Fred: 3 2
我在上一个问题中得到的答案很有吸引力,如果我把eng的名称作为静态行输入,但是它可能会返回大约100个eng,并且真的不想手动更新列表
我可能可以通过SQL函数中的游标来解决这个问题,但是有没有更好的方法呢?将数据从行转换为列被称为。由于您使用的是SQL Server,因此可以使用pivot函数来获得结果 有几种方法可以做到这一点。如果已知数量的
weekof
值,则可以对查询进行硬编码:
select eng,
coalesce([2013-03-03], 0) [2013-03-03],
coalesce([2013-03-10], 0) [2013-03-10]
from
(
select eng, [count], weekof
from RPT_ENG_WEEK
) d
pivot
(
sum([count])
for weekof in ([2013-03-03], [2013-03-10])
) piv;
看
但如果值的数目未知,则需要实现动态SQL以获得结果:
DECLARE @cols AS NVARCHAR(MAX),
@colsNull AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @colsNull = STUFF((SELECT distinct ', coalesce(' + QUOTENAME(cast(weekof as date))+', 0) as '+ QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT eng, ' + @colsNull + '
from
(
select eng, [count], cast(weekof as date) weekof
from RPT_ENG_WEEK
) x
pivot
(
sum([count])
for weekof in (' + @cols + ')
) p '
execute(@query);
| ENG | 2013-03-03 | 2013-03-10 |
-----------------------------------
| Bill | 2 | 0 |
| Fred | 3 | 2 |
| Gary | 15 | 5 |
| James | 11 | 12 |
看。两者都给出了结果:
DECLARE @cols AS NVARCHAR(MAX),
@colsNull AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @colsNull = STUFF((SELECT distinct ', coalesce(' + QUOTENAME(cast(weekof as date))+', 0) as '+ QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT eng, ' + @colsNull + '
from
(
select eng, [count], cast(weekof as date) weekof
from RPT_ENG_WEEK
) x
pivot
(
sum([count])
for weekof in (' + @cols + ')
) p '
execute(@query);
| ENG | 2013-03-03 | 2013-03-10 |
-----------------------------------
| Bill | 2 | 0 |
| Fred | 3 | 2 |
| Gary | 15 | 5 |
| James | 11 | 12 |
将数据从行转换为列称为。由于您使用的是SQL Server,因此可以使用pivot函数来获得结果 有几种方法可以做到这一点。如果已知数量的
weekof
值,则可以对查询进行硬编码:
select eng,
coalesce([2013-03-03], 0) [2013-03-03],
coalesce([2013-03-10], 0) [2013-03-10]
from
(
select eng, [count], weekof
from RPT_ENG_WEEK
) d
pivot
(
sum([count])
for weekof in ([2013-03-03], [2013-03-10])
) piv;
看
但如果值的数目未知,则需要实现动态SQL以获得结果:
DECLARE @cols AS NVARCHAR(MAX),
@colsNull AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @colsNull = STUFF((SELECT distinct ', coalesce(' + QUOTENAME(cast(weekof as date))+', 0) as '+ QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT eng, ' + @colsNull + '
from
(
select eng, [count], cast(weekof as date) weekof
from RPT_ENG_WEEK
) x
pivot
(
sum([count])
for weekof in (' + @cols + ')
) p '
execute(@query);
| ENG | 2013-03-03 | 2013-03-10 |
-----------------------------------
| Bill | 2 | 0 |
| Fred | 3 | 2 |
| Gary | 15 | 5 |
| James | 11 | 12 |
看。两者都给出了结果:
DECLARE @cols AS NVARCHAR(MAX),
@colsNull AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @colsNull = STUFF((SELECT distinct ', coalesce(' + QUOTENAME(cast(weekof as date))+', 0) as '+ QUOTENAME(cast(weekof as date))
from RPT_ENG_WEEK
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT eng, ' + @colsNull + '
from
(
select eng, [count], cast(weekof as date) weekof
from RPT_ENG_WEEK
) x
pivot
(
sum([count])
for weekof in (' + @cols + ')
) p '
execute(@query);
| ENG | 2013-03-03 | 2013-03-10 |
-----------------------------------
| Bill | 2 | 0 |
| Fred | 3 | 2 |
| Gary | 15 | 5 |
| James | 11 | 12 |
您的另一个问题是将MySQL标记为数据库,这是SQL Server,您使用的是什么数据库?两个版本的代码都会非常不同。@bluefeet是的,我知道-这一个来自SQL Server,而不是MySQL(另一个查询是MySQL)。您的另一个问题是将MySQL标记为数据库,这一个是SQL Server,您使用的是什么数据库?这两个版本的代码都会非常不同。@bluefeet是的,我知道-这一个来自SQL Server,而不是MySQL(另一个查询是MySQL),我相当肯定这是voodoo:D绝对精彩@sam.clements LOL,这就是我想确认SQL Server或MySQL的原因,代码非常不同,但您将得到相同的结果。很抱歉出现错误,但我如何在PHP中显示此结果?通常我会按照while($obj=sqlsrv\u fetch\u object($stmt))的思路做一些事情{$eng=$obj->eng;$count=$obj->count;然后显示它,但由于我不知道列标题或行标题,我不确定如何显示它?@sam.clements我不熟悉PHP,我的建议是发布一个新问题。感谢您的帮助-很快就会发布一个新问题!我相当确定这是voodoo:D绝对精彩!@sam.clements LOL,这就是我想确认SQL Server或MySQL的原因,代码非常不同,但您会得到相同的结果。很抱歉出现错误,但我如何在PHP中显示它?通常我会按照while($obj=sqlsrv\fetch\u object($stmt))的思路做一些事情{$eng=$obj->eng;$count=$obj->count;然后显示它,但由于我不知道列标题或行标题,我不确定如何显示它?@sam.clements我不熟悉PHP,我的建议是发布一个新问题。感谢您的帮助-一个新问题很快就会发布!