在php中解析嵌套Json数组

这个JSON数组来自Android，我想把它存储到数据库中。我解析了，但没有插入到数据库中，我如何才能做到这一点

这是我在SQLite数据库中的客户表数组。我是从移动应用程序发送的，我想将其存储在SQLite数据库的用户表中

(
    [0] => Array
        (
            [address] => kabul,Afghanistan
            [fname] => ahmad
            [gender] => Male
            [gfname] => jamal
            [id] => 1
            [name] => Basir ahmad
            [nationId] => 785301
            [phone] => 0772322682
            [picture] => content://com.android.providers.media.documents/document/image%3A22149
        )

    [1] => Array
        (
            [address] => kabul
            [fname] => ali
            [gender] => Female
            [gfname] => ali
            [id] => 2
            [name] => ali
            [nationId] => 78904
            [phone] => 0772322682
            [picture] => content://com.android.providers.media.documents/document/image%3A22149
        )

    [2] => Array
        (
            [address] => kabul,Afghanistan
            [fname] => ahmad
            [gender] => Male
            [gfname] => jamal
            [id] => 1
            [name] => Basir ahmad
            [nationId] => 785301
            [phone] => 0772322682
            [picture] => content://com.android.providers.media.documents/document/image%3A22149
        )

    [3] => Array
        (
            [address] => kabul
            [fname] => ali
            [gender] => Female
            [gfname] => ali
            [id] => 2
            [name] => ali
            [nationId] => 78904
            [phone] => 0772322682
            [picture] => content://com.android.providers.media.documents/document/image%3A22149
        )

)

这是PHP代码

require_once '../connection/connec.php';


 $receved_data = $_POST['userData'];
  $new_array = json_decode($receved_data, true);
  print_r($new_array);

 $res = "";
 for ($i = 0; $i < $receved_data; $i++) {
    foreach ($receved_data->$i as $value) {
           $name = $value['name'];
           $fname = $value['fname'];
          $gfname = $value['gfname'];
          $nationalId = $value['gfname'];
          $gender = $value['gender'];
          $phone = $value['phone'];
          $picture = $value['picture'];
          $address = $value['address'];
          $cosId = $value['costumer_id'];
    }
     print_r(inserInToUser($conn, $name, $fname, $gfname, $nationalId, $gender, $phone, $picture, 
       $address)) ;

   }


     function inserInToUser($conn, $user_name, $user_fname, $user_gfname, $user_nationalId, 
      $user_gender, $user_phone, $user_photo, $user_address)
{
     $query = 'INSERT INTO user (name,fName,gfName,nationalID,gender,phone,picture,address)
           VALUES("' . $user_name . '","' . $user_fname . '","' . $user_gfname . '","' . 
             $user_nationalId . '","' . $user_gender . '"
            ,"' . $user_phone . '","' . $user_photo . '","' . $user_address . '")';

       $result = mysqli_query($conn, $query);
       if ($result) {
         return "Ok";

        } else {
       return $conn->error();
        }
       }

require_once'../connection/connec.php'；
$received_data=$_POST['userData']；
$new_array=json_decode（$received_data，true）；
打印（新阵列）；
$res=”“；
对于（$i=0；$i<$received_data；$i++）{
foreach（$received_data->$i作为$value）{
$name=$value['name']；
$fname=$value['fname']；
$gfname=$value['gfname']；
$national=$value['gfname']；
$gender=$value['gender']；
$phone=$value['phone']；
$picture=$value['picture']；
$address=$value['address']；
$cosId=$value['customer_id']；
}
打印（插入打印机（$conn、$name、$fname、$gfname、$nationalId、$gender、$phone、$picture、，
$address））；
}
函数插入打印机（$conn、$user\u name、$user\u fname、$user\u gfname、$user\u national、，
$user\u性别，$user\u电话，$user\u照片，$user\u地址）
{
$query='插入用户（姓名、fName、gfName、国有、性别、电话、图片、地址）
值（“.$user\u name.”、“.$user\u fname.”、“.$user\u gfname.”、“，”）。
$user\u national.“，”.$user\u性别。”
“.$user\u phone.”、“.$user\u photo.”、“.$user\u address.”等；
$result=mysqli\u查询（$conn，$query）；
如果（$结果）{
返回“Ok”；
}否则{
返回$conn->error（）；
}
}

你希望（$i=0；$i<$received_data；$i++）{的

能做什么。尤其是
$received_data
是你收到的JSON。试着把它注释掉（加上相应的
}
），我怎么做？你的意思是如何注释掉行？在行首添加
/
是一种方法。您应该使用多个插入，