Php 使用preg_replace替换双引号之间的逗号
我有一个像这样的csv文件Php 使用preg_replace替换双引号之间的逗号,php,explode,Php,Explode,我有一个像这样的csv文件 Number,Name,UG College,UG University,PG College,PG University 1100225,Lakshmin,pkrrrr College,"PKRRRRR University, Choice",nandhaaaaa,"Nandhaa University, Kumali" 在读取文件时,我只想在双引号内替换逗号 提前感谢。它假设字符串采用什么编码?preg函数得到了一个u修饰符来设置UTF8,请参见其他函数是bin
Number,Name,UG College,UG University,PG College,PG University
1100225,Lakshmin,pkrrrr College,"PKRRRRR University, Choice",nandhaaaaa,"Nandhaa University, Kumali"
在读取文件时,我只想在双引号内替换逗号
提前感谢。它假设字符串采用什么编码?preg函数得到了一个
u
修饰符来设置UTF8,请参见其他函数是binary-safecreate\u。php 7.2中的函数不推荐使用。有什么解决办法吗?先谢谢你
$string = '1100225,Lakshmin,pkrrrr College,"PKRRRRR University, Choice",nandhaaaaa,"Nandhaa University, Kumali"';
$string = preg_replace_callback(
'|"[^"]+"|',
create_function(
// single quotes are essential here,
// or alternative escape all $ as \$
'$matches',
'return str_replace(\',\',\'*comma*\',$matches[0]);'
),$string );
$array = explode(',',$string);
$array = str_replace('*comma*',',',$array);
print_r($array);
exit;