Php isset功能工作不正常
页面无法看到其代码写在isset function语句下的登录表单。我已经正确地编写了代码并多次执行了它，但是现在在isset语句中编写的代码不起作用。以下是代码：-Php isset功能工作不正常,php,session-variables,isset,Php,Session Variables,Isset,页面无法看到其代码写在isset function语句下的登录表单。我已经正确地编写了代码并多次执行了它，但是现在在isset语句中编写的代码不起作用。以下是代码：- <?php session_start(); echo "<p style=\"font-color: #ff0000;\"> Catogoies </p>"; echo '<link href="var/www/html/sample.css" rel="stylesheet">';
<?php
session_start();
echo "<p style=\"font-color: #ff0000;\"> Catogoies </p>";
echo '<link href="var/www/html/sample.css" rel="stylesheet">';
require_once('../html/conn.php');
$query = "select * from catogories";
mysqli_select_db($dbc, 'odit');
$retrieve = mysqli_query($dbc, $query);
if(!$retrieve)
{
die(mysqli_error($query));
}
while($row=mysqli_fetch_array($retrieve, MYSQL_ASSOC)){
echo "<p style=\"font-color: #ff0000;\">".'<a href="cats.php? catogory='.urldecode($row["Name"]).'">'.$row["Name"].'</a>'."</p>";
$_SESSION['cat']=$row["Name"];
}
if(!($_SESSION)) {
session_start();
}if(isset($_SESSION['lgout']))//the variable logout intialization line
{
if($_SESSION['lgout']!=1||$_SESSION['signup']){
echo "Hello : ".'<a href = "profile.php">'.$_SESSION['unme'].'</a>'; echo "<br><br>";
echo '<a href="logout.php">'."Logout";}
else {
include 'lform.php'; echo "<br><br>";
echo '<a href="Sign_up.php">'."Sign up"."<br>";
} }
mysqli_close($dbc);
//include 'lform.php';
?>
<br>
<a href = 'adding_catogory.php'>Create a New Catogory</a><br><br>
<a href = 'Log_in.php'></a>
<?php
$db = @mysqli_connect("localhost", "oddittor", "Odit@123", "odit");
if(isset($_POST['login'])){
$username=mysqli_real_escape_string($db, $_POST['l_id']);
$password=mysqli_real_escape_string($db, $_POST['pswd']);
$sql="SELECT * from users where usrName='$username' and pswrd = '$password'";
$result = mysqli_query($db, $sql) or die(mysqli_error($db));
$count=mysqli_num_rows($result) or die(mysqli_error($db));
if($count>0) {
$_SESSION['unme']=$username; //This is the global session variable...used for storing the variables across the pages.
$_SESSION['lgout']=0;
header('Location : session.php'.$_SESSION['unme']);
header("Location : Homepage.php".$_SESSION['unme'].$_SESSION['lgout']); header( "refresh:0;url=Homepage.php" );
$_SESSION['unme']=$username;
}
else {
$error = "Invalid Details! Please Renter them"; }
}
?>
<html>
<?php
session_start();
$_SESSION['lgout']=1;
$_SESSION['signup']=0;
echo ' You have been successfully logged out';
header('Location : Homepage.php'.$_SESSION['lgout']);header( "refresh:0;url=Homepage.php" );
?>
</html>
session_start（）
全局显示在页面的开头。由于无法获取会话对象。只需删除即可
session_destroy();
因为您可以访问所有的$\u会话
值
您的查询不安全。使用准备好的语句
而不是所有查询。
你期望什么？您在启动会话后立即销毁会话？第3行中的错误：未启动为什么关闭}
$db=@mysqli\u connect（…mysqli\u real\u escape\u string（）会话销毁主页。phpsession_destroy();