Php 仅验证一层

Php 仅验证一层,php,json,formatting,Php,Json,Formatting,我想验证一个包含json的变量只有一级简单格式。是否有人可以提供一个仅验证一个级别而不是多级别验证的示例 <?php $json = '{"a":1,"b":2,"c":3,"d":4,"e":5}'; isValidOnlayer($json); // True $json = '{ "id": "0001", "type": "donut", "name": "Cake", "ppu": 0.55, "batters": {

我想验证一个包含json的变量只有一级简单格式。是否有人可以提供一个仅验证一个级别而不是多级别验证的示例

   <?php
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
isValidOnlayer($json); // True
$json = '{
    "id": "0001",
    "type": "donut",
    "name": "Cake",
    "ppu": 0.55,
    "batters":
        {
            "batter":
                [
                    { "id": "1001", "type": "Regular" },
                    { "id": "1002", "type": "Chocolate" },
                    { "id": "1003", "type": "Blueberry" },
                    { "id": "1004", "type": "Devil's Food" }
                ]
        },
    "topping":
        [
            { "id": "5001", "type": "None" },
            { "id": "5002", "type": "Glazed" },
            { "id": "5005", "type": "Sugar" },
            { "id": "5007", "type": "Powdered Sugar" },
            { "id": "5006", "type": "Chocolate with Sprinkles" },
            { "id": "5003", "type": "Chocolate" },
            { "id": "5004", "type": "Maple" }
        ]
    }'
    isValidOnlayer($json); // False
?>

您可以使用此功能:

count(array_filter(json_decode($json, 1), 'is_array'))

如果$tmp为
null
,则会发生错误。如果是深度限制,问题将返回
JSON\u ERROR\u depth

层可以是数组/对象/原语,还是仅是对象?
$tmp = json_decode($json, true, 2); // depth=2, the array "itself" is level 1, its elements are level 2