Php MySQL返回多个总数

我有一个简单的MySQL查询：

SELECT who, status, 
COUNT(status) AS Total, completion_status AS Role
FROM `trespondent_360` 
GROUP BY who, status 
ORDER BY who, status

这将正确地返回到数据库中每个人的总数。然后，我需要计算他们的完成状态开始或完成的总数

输出应该类似于：

Who          Total          Status          Completed
Mike Smith   1              Self            1
Mike Smith   5              Other           2
Bob Jones    1              Self            0
Bob Jones    6              Other           5

每当我向上面的代码中添加时，就会得到一个错误，操作数应该包含1列。。见下文

SELECT who, status, 
COUNT(status) AS Total, completion_status AS Role,
(SELECT who, status, COUNT(status) FROM `trespondent_360` 
  WHERE completion_status IN ('Started','Complete')) AS Completed
FROM `trespondent_360` 
GROUP BY who, status 
ORDER BY who, status

---

对于我需要做的任何建议和反馈，我们都将不胜感激。

如果您想计算状态

完成

或

启动

，您可以在以下情况下使用

案例：

SELECT who, status, 
       completion_status AS Role,
       COUNT(status) AS Total,
       COUNT(CASE WHEN status IN ('Started','Complete') THEN 1 END) AS Completed
FROM `trespondent_360` 
GROUP BY who, status 
ORDER BY who, status;

顺便说一下，您应该在
completion\u status
列上使用聚合函数，我知道它可以用于MySQL，但它不符合ANSI标准
也请欣赏关于
聚合功能的说明。