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Php 移动上载的文件_Php_Html_File Upload_Mysqli - Fatal编程技术网

Php 移动上载的文件

Php 移动上载的文件,php,html,file-upload,mysqli,Php,Html,File Upload,Mysqli,我看不出我错过了什么。。我试图让用户上传一个文件,以便在社交媒体网站上发布图片,我已经这样做了,这样他们可以选择一张个人资料图片,效果很好,但由于某种原因,这不起作用 <div class = "midCol"><?php //show post box ?><form method = "post" action = "<?php echo $_SERVER['PHP_SELF']; ?>"> <div class

我看不出我错过了什么。。我试图让用户上传一个文件,以便在社交媒体网站上发布图片,我已经这样做了,这样他们可以选择一张个人资料图片,效果很好,但由于某种原因,这不起作用

<div class = "midCol"><?php

    //show post box
    ?><form method = "post" action = "<?php echo $_SERVER['PHP_SELF']; ?>">
    <div class = "box" style = "width:500px;">
        <textarea class = "poster" rows="5" cols="50" id = "area" name = "area" value = "area"
        placeholder = "What's on your mind?"></textarea><br/>
        <input type = "file" id = "picture" name = "picture"/><br/>
        <input type = "Submit" value = "Post" name = "post"/><br/>

    </div>
</form><?php

它有点乱,因为我一直在左右更改它,稍后我会清理它,但是有人看到我做错了什么吗???

您的表单缺少
enctype=“multipart/form data”

将其更改为:

<form method = "post" enctype="multipart/form-data" action = "<?php echo $_SERVER['PHP_SELF']; ?>">

您的表单丢失
enctype=“多部分/表单数据”

将其更改为:

<form method = "post" enctype="multipart/form-data" action = "<?php echo $_SERVER['PHP_SELF']; ?>">

您的表单丢失
enctype=“多部分/表单数据”

将其更改为:

<form method = "post" enctype="multipart/form-data" action = "<?php echo $_SERVER['PHP_SELF']; ?>">

您的表单丢失
enctype=“多部分/表单数据”

将其更改为:

<form method = "post" enctype="multipart/form-data" action = "<?php echo $_SERVER['PHP_SELF']; ?>">

它一直在说“未知索引图片”,但我认为图片索引在HTML中定义得很清楚/它一直在说“未知索引图片”,但我认为图片索引在HTML中有明确的定义/它一直在说“未知索引图片”,但我认为图片索引在HTML中有明确的定义/它一直在说“未知索引图片”,但我认为图片索引在HTML中有明确的定义/非常感谢你!我快疯了!非常感谢你!我快疯了!非常感谢你!我快疯了!非常感谢你!我快疯了!