如何在php中编写一个curl来访问php中的一些数据？

我有一个curl代码，如下所示：

curl --request GET \
--user 60CF3Ce97nRS1Z1Wp5m9kMmzHHEh8Rkuj31QCtVxjPWGYA9FymyqsK0Enm1P6mHJf0THbR:API-P4ss \
https://api.sandbox.ewaypayments.com/Transaction/44DD7aVwPYUPemGRf7pcWxyX2FJS-0Wk7xr9iE7Vatk_5vJimEbHveGSqX52B00QsBXqbLh9mGZxMHcjThQ_ITsCZ3JxKOY88WOVsFTLPrGtHRkK0E9ZDVh_Wz326QZlNlwx2

---

我想在php文件中编写此代码。我不知道如何开始写这段代码。有人能告诉我如何用php编写curl代码吗？

首先使用file\u get\u contents php函数

如果找不到解决方案，请尝试以下代码

//  Initiate curl
$ch = curl_init();
// Disable SSL verification
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
// Will return the response, if false it print the response
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// Set the url
curl_setopt($ch, CURLOPT_URL,$url);
// Execute
$result=curl_exec($ch);
// Closing
curl_close($ch);

// Will dump a beauty json :3
var_dump(json_decode($result, true));

---

首先使用file_get_contents php函数

如果找不到解决方案，请尝试以下代码

//  Initiate curl
$ch = curl_init();
// Disable SSL verification
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
// Will return the response, if false it print the response
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// Set the url
curl_setopt($ch, CURLOPT_URL,$url);
// Execute
$result=curl_exec($ch);
// Closing
curl_close($ch);

// Will dump a beauty json :3
var_dump(json_decode($result, true));

试试这个：

$url = 'API URL';

try {
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    $APIresponse = curl_exec($ch);
    curl_close($ch);
    $res = json_decode($APIresponse, true);
    // $res contains the API response as an array
}
catch(Exception $e)
{
    // Error mesage
}

试试这个：

$url = 'API URL';

try {
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    $APIresponse = curl_exec($ch);
    curl_close($ch);
    $res = json_decode($APIresponse, true);
    // $res contains the API response as an array
}
catch(Exception $e)
{
    // Error mesage
}

您需要使用

代码的解决方案：

<?php
$username = "60CF3Ce97nRS1Z1Wp5m9kMmzHHEh8Rkuj31QCtVxjPWGYA9FymyqsK0Enm1P6mHJf0THbR";
$password = "API-P4ss";
$process = curl_init("https://api.sandbox.ewaypayments.com/Transaction/44DD7aVwPYUPemGRf7pcWxyX2FJS-0Wk7xr9iE7Vatk_5vJimEbHveGSqX52B00QsBXqbLh9mGZxMHcjThQ_ITsCZ3JxKOY88WOVsFTLPrGtHRkK0E9ZDVh_Wz326QZlNlwx2");
curl_setopt($process, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
curl_setopt($process, CURLOPT_HEADER, 1);
curl_setopt($process, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($process, CURLOPT_TIMEOUT, 30);
curl_setopt($process, CURLOPT_POST, 1);
curl_setopt($process, CURLOPT_RETURNTRANSFER, TRUE);
$return = curl_exec($process);
curl_close($process);
var_dump($return);

您需要使用

代码的解决方案：

<?php
$username = "60CF3Ce97nRS1Z1Wp5m9kMmzHHEh8Rkuj31QCtVxjPWGYA9FymyqsK0Enm1P6mHJf0THbR";
$password = "API-P4ss";
$process = curl_init("https://api.sandbox.ewaypayments.com/Transaction/44DD7aVwPYUPemGRf7pcWxyX2FJS-0Wk7xr9iE7Vatk_5vJimEbHveGSqX52B00QsBXqbLh9mGZxMHcjThQ_ITsCZ3JxKOY88WOVsFTLPrGtHRkK0E9ZDVh_Wz326QZlNlwx2");
curl_setopt($process, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
curl_setopt($process, CURLOPT_HEADER, 1);
curl_setopt($process, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($process, CURLOPT_TIMEOUT, 30);
curl_setopt($process, CURLOPT_POST, 1);
curl_setopt($process, CURLOPT_RETURNTRANSFER, TRUE);
$return = curl_exec($process);
curl_close($process);
var_dump($return);

一个好的起点应该是curl_init（）中添加了哪个值？@johanna这是指向页面的url。url是常量吗？输出如下所示：string（66）“HTTP/1.1400坏_请求内容长度：0连接：Close”有人能回答我的问题吗？在curl_init（）中正在添加哪个值？@johanna这是指向页面的url。该url是否为常量？输出如下所示：字符串（66）“HTTP/1.1 400错误请求内容长度：0连接：关闭”有人能回答我的问题吗？