Php 选择带有.$row的语句

我想知道这个select语句有什么问题。 这就是我得到的错误：

分析错误：语法错误，意外的T_封装_和_空白， 中应为T\u字符串、T\u变量或T\u NUM\u字符串 /home/www/mp28.bit-mp.biz/CardRegistration2.php，第47行

应该是

$query = "SELECT PlayerName FROM Players where TeamName = '{$row['Team1']}'";

---

查询更正检查两个解决方案。两者都应该起作用：

$query = "SELECT PlayerName FROM Players where TeamName =" .$row['Team1'];

或

TeamName=

$query = "SELECT PlayerName FROM Players where TeamName = '".$row['Team1']."' ";

---

试试这个。TeamName列是varchar，因此传递带有

引号的字符串

我想用两个不同列的值填充下拉列表，例如客场与主场xxx与yyy我想填充一个下拉列表：---选择--xxx yyy任何人都可以帮助我吗？？

$query = "SELECT PlayerName FROM Players where TeamName =" .$row['Team1'];

$query = "SELECT PlayerName FROM Players where TeamName ='" .$row['Team1'] . "'";

$query = "SELECT PlayerName FROM Players where TeamName = '".$row['Team1']."' ";