Php mysql\u fetch\u数组发出警告

我对mysql\u fetch\u数组有问题。我得到一个警告：

mysql_fetch_array() expects parameter 1 to be resource, boolean given in D:\wamp\www\bb.php on line 6 bool(false) 

这是我的密码：

if (isset($_POST['chapter'])AND isset($_POST['verse'])){
  $db=mysql_connect("localhost","fruanthony","admin");  
  mysql_select_db("gths",$db);  
  $results=mysql_query("SELECT * FROM bible where verse=".$_POST['verse']."AND            chapter=".$_POST['chapter']);  
  while($a=mysql_fetch_array($results)){    
   echo $a['info'] ;
   echo "<br>";  
  }  
}

查询值中缺少单引号。$\u POST['chapter']”。请注意单引号替换

$results=mysql\u querySELECT*来自圣经，其中韵文=。$\u POST['verse']和 章=.$_POST[“章”]

到

现在试试：

if (isset($_POST['chapter']) AND isset($_POST['verse'])) {

// Dont ignore SQL injection
    $safeChapter = mysql_real_escape_string($_POST['chapter']);
    $safeVerse = mysql_real_escape_string($_POST['verse']);


    $db=mysql_connect("localhost","fruanthony","admin");  
    mysql_select_db("gths",$db);  
    $results=mysql_query("SELECT * FROM bible where verse='".$safeVerse."' AND chapter='".$safeChapter."';");  
    while($a=mysql_fetch_array($results))  
    {    
        echo $a['info'] ;
        echo "<br>";  
    }  
}

---

这与Java有什么关系？它看起来像MySQL和PHP…顺便说一句，你的代码中几乎所有的东西都是不好的做法，从圣经中获取东西。我已经这样做了，但是如果你做的很好，查询不会返回任何东西。

$results=mysql_query("SELECT * FROM bible where verse = '".$_POST['verse']."' AND chapter = '".$_POST['chapter']."'");

if (isset($_POST['chapter']) AND isset($_POST['verse'])) {

// Dont ignore SQL injection
    $safeChapter = mysql_real_escape_string($_POST['chapter']);
    $safeVerse = mysql_real_escape_string($_POST['verse']);


    $db=mysql_connect("localhost","fruanthony","admin");  
    mysql_select_db("gths",$db);  
    $results=mysql_query("SELECT * FROM bible where verse='".$safeVerse."' AND chapter='".$safeChapter."';");  
    while($a=mysql_fetch_array($results))  
    {    
        echo $a['info'] ;
        echo "<br>";  
    }  
}