Warning: file_get_contents(/data/phpspider/zhask/data//catemap/8/mysql/70.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
php和mysql的注册页面不工作_Php_Mysql - Fatal编程技术网

php和mysql的注册页面不工作

php和mysql的注册页面不工作,php,mysql,Php,Mysql,试图创建一个注册页面,用php将新用户添加到数据库中,我似乎无法获得要添加到数据库中的信息,这很可能是我做错了或在代码中遗漏了一些愚蠢的事情 这是我的密码 <?php session_start(); ?> <!DOCTYPE html> <html class="no-js"> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-

试图创建一个注册页面,用php将新用户添加到数据库中,我似乎无法获得要添加到数据库中的信息,这很可能是我做错了或在代码中遗漏了一些愚蠢的事情

这是我的密码

<?php
    session_start();
?>

<!DOCTYPE html>
<html class="no-js">
<head>
        <meta charset="utf-8" />
        <meta http-equiv="X-UA-Compatible" content="IE=edge" />


    <title></title>
    <meta name="author" content="" />
    <meta name="description" content="" />

        <meta name="viewport" content="width=device-width, initial-scale=1" />


        <script src="boilerplate/js/vendor/modernizr-2.7.1.min.js"></script>


    <link rel="stylesheet" type="text/css" href="../css/party.css" media="screen" />

    <script type="text/javascript" src="javascript/jquery_min.js"></script>

    <script type="text/javascript" src="javascript/cookies.js"></script>


</head>

<body>




<?php include 'header.php'; ?>

<div id="container_register">

<div id="content_register">

    <h2>Register</h2>

    <?php
include "connect.php";
if (isset($_POST['formsubmitted'])) {
    $error = array(); //Declare An Array to store any error message

    if (empty($_POST['up_username'])) { //if no name has been supplied
        $error[] = 'Please Enter a name '; //add to array "error"
    } else {
        $name = $_POST['up_username']; //else assign it a variable

    }

    if (empty($_POST['up_email'])) {

        $error[] = 'Please Enter your Email ';

    } else {

if (preg_match("/^([a-zA-Z0-9])+([a-zA-Z0-9\._-])*@([a-zA-Z0-9_-])+([a-zA-Z0-9\._-]+)+$/",

            $_POST['up_email'])) {

            //regular expression for email validation

            $Email = $_POST['up_email'];

        } else {

            $error[] = 'Your EMail Address is invalid  ';

        }

 }


    if (empty($_POST['up_password'])) {

        $error[] = 'Please Enter Your Password ';

    } else {

        $Password = $_POST['up_password'];

    }

if (empty($error)) //send to Database if there's no error '



{ // If everything's OK...



        // Make sure the email address is available:

        $query_verify_email = "SELECT * FROM users  WHERE Email ='$Email'";

        $result_verify_email = mysqli_query($dbc, $query_verify_email);

        if (!$result_verify_email) { //if the Query Failed ,similar to if($result_verify_email==false)

            echo ' Database Error Occured ';

        }
if (mysqli_num_rows($result_verify_email) == 0) { // IF no previous user is using this email .



            // Create a unique  activation code:


            $query_insert_user =

                "INSERT INTO `users` ( `Username`, `Email`, `Password`) VALUES ( '$name', '$Email', '$Password')";


$result_insert_user = mysqli_query($dbc, $query_insert_user);

            if (!$result_insert_user) {

                echo 'Query Failed ';

            }

 echo '<div class="success">Thank you for

registering! </div>';

             } else { // If it did not run OK.
                echo '<div class="errormsgbox">You could not be registered due to a systemdiv>';

            }


        } else { // The email address is not available.

            echo '<div class="errormsgbox" >That email address has already been registered.</div>';

        }



    } else { //If the "error" array contains error msg , display them



        echo '<div class="errormsgbox"> <ol>';

        foreach ($error as $key => $values) {



            echo '  <li>' . $values . '</li>';



        }

        echo '</ol></div>';



    }



    mysqli_close($dbc); //Close the DB Connection

// End of the main Submit conditional.
    ?>

        <form name="signup" id="signup" action="register.php" method="post">

            <label for="up_username"><span class="required">*</span> Name</label>
            <input type="text" name="up_username" id="up_username" placeholder="First Surname" />

<br>
            <label for="up_email"><span class="required">*</span> Email</label>
            <input type="email" name="up_email" id="up_email" placeholder="username@email.com" />

<br>
            <label for="up_password"><span class="required">*</span> Password</label>
            <input type="password" name="up_password" id="up_password" />

<br>
            <label for="up_password_c"><span class="required">*</span> Confirm Password</label>
            <input type="password" name="up_password_c" id="up_password_c" />


            <div class="div_submit">

                <input id="register_submit" type="submit" value="Sign up" />
            </div>

        </form><!--#sign up end-->

    <p class="required">* Indicates a required field</p>

</div><!--content div end-->

</div><!--container div end-->

登记

您编写的If条件始终为retrun false

要解决此问题,请将submit按钮的name属性设置为
formsubmitted
,如下所示

<input id="register_submit" name= "formsubmitted" type="submit" value="Sign up" />


由于表单中不存在
formsubmitted
,因此没有为
$\u POST['formsubmitted']
设置值,因此If语句的
If部分永不会执行。

这是我经常使用的类似脚本,请随意修改

<? 
  if ($_POST['submit']){
    $username = $_POST['username'];
    $password = md5($_POST['password']);
    $confirm = $_POST['confirm'];
    $email = $_POST['email'];

if (!$username || !$password || !$confirm || !$email){
    $response = "Please fill in all the boxes";
}else{

    $check = mysql_num_rows(mysql_query("SELECT * FROM users WHERE username='$username'"));
    if ($check != 0){
        $response = "Username taken, Please choose an alternative";
    }else{

    $check = mysql_num_rows(mysql_query("SELECT * FROM users WHERE email='$email'"));
    if ($check != 0){
        $response = "This Email has already been registered";
    }else{


            mysql_query("INSERT INTO `users` (`id`, `username`, `password`, `email`) VALUES ('', '$username', '$password', '$email');");
$response = "Account Created";

}
}
}
}

echo "$response"; ?>

打开文件后立即将错误报告添加到文件顶部
了解一下它在做什么-所有这些都是错误的-会很好…这其中哪部分不起作用?您是否做了任何事情来确定脚本的哪一部分失败了(您是否成功接收到POST信息,是否成功连接到数据库,等等?)?感谢您提供了我不知道的错误代码。在旁注中,使用
mysqli\ucode>函数是一个很好的步骤,但不足以阻止SQL注入。您需要使用参数化查询,因为上面的代码可能会被注入。这不是登录系统,这会使您的站点完全崩溃。你没有任何东西,所以它充满了,你使用MD5作为密码,这是严重错误的,而且你还使用了不推荐的、超级糟糕的
mysql\u查询接口。请删除此答案。另外,我会检查一下你部署的任何站点是否被黑客入侵,因为这需要大约两秒钟的时间。