Php 如何检查数组的一个元素是否存在于另一个数组中
我所尝试的:Php 如何检查数组的一个元素是否存在于另一个数组中,php,arrays,multidimensional-array,php-7,Php,Arrays,Multidimensional Array,Php 7,我所尝试的: $result = array(); $A= Array ( [0] => Array ( [id] => 1946 [name] => cook [pic] => cookpic.png ) ) $B = Array ( [0] => Array ( [id] => 1944 [name] =&g
$result = array();
$A= Array
(
[0] => Array
(
[id] => 1946
[name] => cook
[pic] => cookpic.png
)
)
$B = Array
(
[0] => Array
(
[id] => 1944
[name] => driver
[pic] => driver.png
)
[1] => Array
(
[id] => 934
[name] => developer
[pic] => developer.jpg
)
[2] => Array
(
[id] => 1946
[name] => cook
[pic] => cookpic.png
)
)
我有两个数组,我使用var\u dump
来显示它们,并且可以在上面看到它们
我想要实现的是,我想要比较两种职业,并且想要独特的
$result
数组。现在,如果Cook在$B中不存在,那么Cook应该被推入$B
数组,这将成为$result
,否则它不应该被推入。执行$result=!空(数组_相交($a,$b))
只会告诉您$a
和$b
之间是否存在公共元素
$result = !empty(array_intersect($a, $b));
您可以使用,但它不适用于多维数组。所以你必须从头开始
编辑:
合并两个数组,然后使用array\u map应用array\u unique删除重复项使用stracecmp()
内置函数进行比较。然后使用array\u push()
。
你可以使用暴力手段。但我相信你能从中得到更好的答案
$result = array();
$a = array(
array(
"id" => 1946,
"name" => "Cook", // upper case C
"pic" => "cookpic.png"
),
array(
"id" => 1946,
"name" => "cook", // lower case c
"pic" => "cookpic.png"
)
);
$b = array(
array(
"id" => 1944,
"name" => "driver",
"pic" => "driver.png"
),
array(
"id" => 934,
"name" => "developer",
"pic" => "developer.png"
),
array(
"id" => 1946,
"name" => "cook", // lower case c
"pic" => "cookpic.png"
)
);
$m = array_merge($a, $b);
$result = array_map("unserialize", array_unique(array_map("serialize", $m)));
print_r($result);
$result=array();
$A[0]=数组(“id”=>1946,“name”=>Cook,“pic”=>cookpic.png);
$B[0]=数组(“id”=>1944,“name”=>driver,“pic”=>driver.png);
$B[1]=数组(“id”=>934,“name”=>developer,“pic”=>developer.jpg);
$B[2]=数组(“id”=>1946,“name”=>cook,“pic”=>cookpic.png);
foreach($A作为$key=>$value)
{
foreach($B作为$key1=>$value1)
{
如果(!strcasecmp($value[“name”],$value1[“name”]))
{array_push($result,$value);}
}
}
回声(“”);打印(结果);
你能给我们看一下你的计划吗?我试过像result=那样使用array\u intersect!空(数组_相交($a,$b))代码>但它不工作,因为数组中有数组。有什么建议吗@请更新您的问题,以便每个人都可以查看您的尝试和结果,以便我们可以帮助您完成任务。对不起,你的名字有些变化。只有diff是您的$result
只提供了非唯一的数组,但我希望$result
中的数组应该包含$a
和$b
中的唯一数组。比如,如果我搜索“cook”,那么我的结果数组应该包含$b的所有元素,并且只有一次$a的cook
$result = array();
$a = array(
array(
"id" => 1946,
"name" => "Cook", // upper case C
"pic" => "cookpic.png"
),
array(
"id" => 1946,
"name" => "cook", // lower case c
"pic" => "cookpic.png"
)
);
$b = array(
array(
"id" => 1944,
"name" => "driver",
"pic" => "driver.png"
),
array(
"id" => 934,
"name" => "developer",
"pic" => "developer.png"
),
array(
"id" => 1946,
"name" => "cook", // lower case c
"pic" => "cookpic.png"
)
);
$m = array_merge($a, $b);
$result = array_map("unserialize", array_unique(array_map("serialize", $m)));
print_r($result);
$result=array();
$A[0]=array("id" => 1946, "name" => Cook, "pic" => cookpic.png);
$B[0]=array("id" => 1944, "name" => driver, "pic" => driver.png);
$B[1]=array("id" => 934, "name" => developer, "pic" => developer.jpg);
$B[2]=array("id" => 1946, "name" => cook, "pic" => cookpic.png);
foreach ($A as $key => $value)
{
foreach ($B as $key1 => $value1)
{
if (!strcasecmp($value["name"], $value1["name"]))
{ array_push($result, $value); }
}
}
echo("<pre>");print_r($result);