Php Mysql从两个表中获取min、avg和latest（产品和产品价格）

我有两个Mysql表：

具有id、名称、链接的产品 带id、id\U产品、价格、可用性和日期的产品价格 在第二个例子中，您可以看到，根据更新时间的不同，同一产品可以有更多的价格，我想做的是有一个查询来显示最低价格、平均价格和最新价格。我可以在一个查询中得到前两个最低和平均价格，在另一个查询中得到最新价格，但我不知道如何连接它们，或者是否有其他方法

我的第一个查询如下所示：

SELECT 
    `products`.id AS ids, `products`.name, `products`.link, 
    `products-prices`.id AS id_p, `products-prices`.price, 
    `products-prices`.availability, `products-prices`.date, 
    AVG(`products-prices`.price) AS medie, 
    MIN(`products-prices`.price) AS minim 
FROM
    `products-prices` 
INNER JOIN 
    `products` ON `products`.id = `products-prices`.id_produs 
GROUP BY 
    ids 
ORDER BY 
    ids 

第二个是：

SELECT * 
FROM `products-prices`
WHERE date IN (SELECT DISTINCT MAX(date) max_date 
               FROM `products-prices` 
               GROUP BY id_produs) 

你能告诉我如何把它们结合起来吗？多谢各位

我不知道工会是如何运作的，如果它能运作，我会试试

---

//编辑：我还有另一个问题，我能在数据库中没有最新条目的情况下获得最小、平均值吗？

您可以使用子选择来获得最大日期

  select 
      `products`.id AS ids, 
      `products`.name, 
      `products`.link,
      t.date,
      t.price,
      t.availability,
       AVG(`products-prices`.price) AS medie, 
       MIN(`products-prices`.price) AS minim 

  from  `products`
  inner join `products-prices`  ON `products`.id=`products-prices`.id_produs 
  inner join ( )
  select id_produs, date, price, availability
  from `products-prices` 
  where ( id_produs, date ) = (
  select id_produs, max(date) as max_date
  from `products-prices` 
  group by id ) t on t.id_produs = `products`.id_prod

---

您可以使用“最大日期”的子选择

  select 
      `products`.id AS ids, 
      `products`.name, 
      `products`.link,
      t.date,
      t.price,
      t.availability,
       AVG(`products-prices`.price) AS medie, 
       MIN(`products-prices`.price) AS minim 

  from  `products`
  inner join `products-prices`  ON `products`.id=`products-prices`.id_produs 
  inner join ( )
  select id_produs, date, price, availability
  from `products-prices` 
  where ( id_produs, date ) = (
  select id_produs, max(date) as max_date
  from `products-prices` 
  group by id ) t on t.id_produs = `products`.id_prod

---

这是一个未经测试的解决方案，如果有帮助，请告诉我

SELECT 
    `products`.id AS ids, `products`.name, `products`.link, 
    `products-prices`.id AS id_p, `products-prices`.price, 
    `products-prices`.availability, `products-prices`.date, 
    AVG(`products-prices`.price) AS medie, 
    MIN(`products-prices`.price) AS minim,
    latest.`date` as latest_date,
    latest.price as latest_price 
FROM
    `products-prices` 
INNER JOIN 
    `products` ON `products`.id = `products-prices`.id_produs 
INNER JOIN
    (select id_produs, price, `date` 
     from `products-prices` t1
     where not exists (select 1
                       from `products-prices` t2
                       where t1.`date` < t2.`date` and t1.id_produs = t2.id_produs)
     group by id_produs
    ) latest     
ON
    latest.id_produs = products.id
GROUP BY 
    ids 
ORDER BY 
    ids 

---

这是一个未经测试的解决方案，如果有帮助，请告诉我

SELECT 
    `products`.id AS ids, `products`.name, `products`.link, 
    `products-prices`.id AS id_p, `products-prices`.price, 
    `products-prices`.availability, `products-prices`.date, 
    AVG(`products-prices`.price) AS medie, 
    MIN(`products-prices`.price) AS minim,
    latest.`date` as latest_date,
    latest.price as latest_price 
FROM
    `products-prices` 
INNER JOIN 
    `products` ON `products`.id = `products-prices`.id_produs 
INNER JOIN
    (select id_produs, price, `date` 
     from `products-prices` t1
     where not exists (select 1
                       from `products-prices` t2
                       where t1.`date` < t2.`date` and t1.id_produs = t2.id_produs)
     group by id_produs
    ) latest     
ON
    latest.id_produs = products.id
GROUP BY 
    ids 
ORDER BY 
    ids 

---

不要在表/列标识符中使用“-”。这肯定会造成严重后果。我正在根据类别名称自动生成数据库，如www.something.com/video-cards/->视频卡和视频卡的价格，因此即使我从价格中削减，我仍然在类别名称中保留它。谢谢您的警告，我将尝试做一些事情。不要在表/列标识符中使用“-”。这肯定会造成严重后果。我正在根据类别名称自动生成数据库，如www.something.com/video-cards/->视频卡和视频卡的价格，因此即使我从价格中削减，我仍然在类别名称中保留它。我会尽力做点什么，谢谢你的警告。