Php 如何显示不同的默认表内容以及单击按钮时,UI中相同表中的表内容应不同?
我有一个显示用户的代码,还有一个删除用户的删除按钮。当我删除任何用户时,已删除的用户将从用户列表中删除。在上面我有两个按钮,一个是创建用户,另一个是显示所有删除的用户。单击下表中显示所有用户的“查看已删除用户”按钮时,如何显示已删除的用户 下面是代码Php 如何显示不同的默认表内容以及单击按钮时,UI中相同表中的表内容应不同?,php,html,mysql,Php,Html,Mysql,我有一个显示用户的代码,还有一个删除用户的删除按钮。当我删除任何用户时,已删除的用户将从用户列表中删除。在上面我有两个按钮,一个是创建用户,另一个是显示所有删除的用户。单击下表中显示所有用户的“查看已删除用户”按钮时,如何显示已删除的用户 下面是代码 <body class="back-color"> <div class="container"> <div class="table-wrapper"> <
<body class="back-color">
<div class="container">
<div class="table-wrapper">
<div class="table-title">
<div class="row">
<div class="col-sm-7">
<h2><b>Manage Users</b></h2>
</div>
<div class="col-sm-3">
<a href="" class="btn btn-primary" data-toggle="modal"><i class="material-icons">info</i> <span>View Deleted Users</span></a>
</div>
<div class="col-sm-2">
<a href="crtusr.php" class="btn btn-success" data-toggle="modal"><i class="material-icons"></i> <span>Add New User</span></a>
</div>
</div>
</div>
<?php
if($no_of_users>1){
echo '<table class="paginated table table-striped table-hover">
<thead>
<tr>
<th></th>
<th>Username</th>
<th>Email</th>
<th>Role</th>
</tr>
</thead>
<tbody>';
while($userdetails = mysqli_fetch_array($user_details, MYSQLI_ASSOC)){
echo' <tr>
<td></td>
<td>'.$userdetails['username'].'</td>
<td>'.$userdetails['email'].'</td>
<td>'.$userdetails['role'].'</td>
<td>
<a href="" class="edit" data-toggle="modal"><i class="material-icons" data-toggle="tooltip" title="Edit"></i></a>
<a href="" class="delete" name="delete" data-toggle="modal" Onclick="return ConfirmDelete()"><i class="material-icons" data-toggle="tooltip" title="Delete"></i></a>
</td>
</tr>';
}
echo '</tbody>
</table>';
}
?>
</div>
</div>
</body>
管理用户
我想您需要一个软删除选项
步骤:
//if retrieving undeleted users from table
$sql = "SELECT * FROM users from is_deleted = 0";
//else retrieving deleted users from table
$sql = "SELECT * FROM users from is_deleted = 1";
//$con holding your database connection details
$user_details= mysqli_query($con,$sql);
while($userdetails = mysqli_fetch_array($user_details, MYSQLI_ASSOC)) {
// $userdetails array contains the data of a user
// iterate it and fill your table accordingly
}
希望这能奏效。我想你需要一个软删除选项 步骤:
//if retrieving undeleted users from table
$sql = "SELECT * FROM users from is_deleted = 0";
//else retrieving deleted users from table
$sql = "SELECT * FROM users from is_deleted = 1";
//$con holding your database connection details
$user_details= mysqli_query($con,$sql);
while($userdetails = mysqli_fetch_array($user_details, MYSQLI_ASSOC)) {
// $userdetails array contains the data of a user
// iterate it and fill your table accordingly
}
希望这能奏效。是的,我也做了同样的事情,我也有疑问。但是我怎样才能在UI@ved的同一个表中显示删除的用户详细信息呢?我想每次从表中检索数据的查询都需要修改,是的,我也做了同样的操作,我也有查询。但是我如何在UI@ved上的同一个表中显示删除的用户详细信息呢?我认为从表中检索数据的查询每次都需要修改,