Php 选择表中的所有数据，同时用另一个表中的值替换列？

目前，我有两个表，约会和用户：

appointment_id | time | teacher_id | student_id 1 | 11 | 2 | 1 2 | 12 | 2 | 1 user_id | name 1 | student 2 | teacher 预约|时间|教师|学生|学生 1 | 11 | 2 | 1 2 | 12 | 2 | 1 用户名 1 |学生 2 |教师 预期结果：

appointment_id | time | teachername | studentname 1 | 11 | teacher | student 2 | 12 | teacher | student 预约|时间|教师姓名|学生姓名 1 | 11 |教师|学生 2 | 12 |教师|学生 基本上，我希望从约会表中执行SELECT*操作，但我不希望查询给我id，而是希望用名称替换它们。我试着创建一个临时表和一个连接，但没有找到答案。任何帮助都会很好，谢谢

这个怎么样

SELECT
    appointment_id,
    time,
    u.name AS teachername,
    v.name AS studentname
FROM
    appointments AS a
LEFT JOIN
    users AS u ON
    a.teacher_id = u.user_id
LEFT JOIN
    users AS v ON
    a.student_id = v.user_id

你可以签入这个

这个怎么样

SELECT
    appointment_id,
    time,
    u.name AS teachername,
    v.name AS studentname
FROM
    appointments AS a
LEFT JOIN
    users AS u ON
    a.teacher_id = u.user_id
LEFT JOIN
    users AS v ON
    a.student_id = v.user_id

您可以签入这个

试试这个

   select a.appointment_id , a.time ,b.name as teachername ,
          c.name as studentname
   from appointments a 
   inner join users b
   on a.teacher_id = b.user_id
   inner join users c
   on a.student_id = c.user_id

输出：

   APPOINTMENT_ID   TIME    TEACHERNAME     STUDENTNAME
          1          11     teacher         student
          2          12     teacher         student

试试这个

   select a.appointment_id , a.time ,b.name as teachername ,
          c.name as studentname
   from appointments a 
   inner join users b
   on a.teacher_id = b.user_id
   inner join users c
   on a.student_id = c.user_id

输出：

   APPOINTMENT_ID   TIME    TEACHERNAME     STUDENTNAME
          1          11     teacher         student
          2          12     teacher         student

---

. . 你试过什么？这是一个非常基本的SQL查询，所以如果您有编写查询的经验，应该不难理解。你试过什么？这是一个非常基本的SQL查询，因此如果您有编写查询的经验，应该不难理解。我想您希望

u.name作为teachername，v.name作为studentname

我想您希望

u.name作为teachername，v.name作为studentname