Php 从2个表中选择（Kohana框架）

我有两个数据结构相同的表

例：

如何从两个表中获取Kohana框架数据 然后按天计算结果？ 另外，我如何将一个字符串替换为substr，并将该字符串的其余部分相加（这是一个数字？请查看示例中的package_credit_uuu行）

例如，如果我有以下数据：

Table1: 
(1, 200, "package_credit_300", "12.12.12 12:02:34"), 
(2, 50, "package_credit_50", "12.12.12 15:17:02"), 
(2, 50, "package_credit_50", "13.12.12 16:12:12")

Table2: 
(1, 50, "package_credit_50", "13.12.12 12:02:34"), 
(2, 50, "package_credit_50", "13.12.12 15:17:02"), 
(2, 200, "package_credit_300", "14.12.12 16:12:12")

我想得到这样的东西：

Date: 12.12.12 - Credit: 350 - Paid: 250
Date: 13.12.12 - Credit: 150 - Paid: 150
Date: 14.12.12 - Credit: 300 - Paid: 200

---

在Kohana中使用ORM或ActiveRecord无法做到这一点。您需要执行此自定义sql

SELECT Date(t.`date`)                                    AS `Date`, 
       Sum(Cast(Substring(t.`package`, 16) AS UNSIGNED)) AS `Credit`, 
       Sum(t.pay_amount)                                 AS `Paid` 
FROM   (SELECT * 
        FROM   table1 
        UNION 
        SELECT * 
        FROM   table2) AS `t` 
GROUP  BY `Date` 
ORDER  BY `Date` ASC 

试试这个

   SELECT Substring(t.`date`,1,8)                        AS dates, 
   Sum(Cast(Substring(t.`package`, 16) AS UNSIGNED)) AS `Credit`, 
   Sum(t.pay_amount)                                 AS `Paid` 
    FROM   (SELECT * 
    FROM   table1 
    UNION 
    SELECT * 
    FROM   table2) AS `t` 
    GROUP  BY dates 
    ORDER  BY dates ASC 

---

日期不是mysql日期格式。是的，但它不是我使用的值。这只是一个示例，因此您可以忽略格式：）

   SELECT Substring(t.`date`,1,8)                        AS dates, 
   Sum(Cast(Substring(t.`package`, 16) AS UNSIGNED)) AS `Credit`, 
   Sum(t.pay_amount)                                 AS `Paid` 
    FROM   (SELECT * 
    FROM   table1 
    UNION 
    SELECT * 
    FROM   table2) AS `t` 
    GROUP  BY dates 
    ORDER  BY dates ASC