Php 上载文件时出错
我想将图像从galery上传到服务器。我成功上传图像,但我只能上传一个文件。如果我上传2个文件,第2个文件将被上传。第一个文件将不会上载。或者,如果我编辑并上传第二个图像文件,则第一个图像文件将被第二个图像文件替换 这是webservicecontroller.phpPhp 上载文件时出错,php,android,cakephp,file-upload,Php,Android,Cakephp,File Upload,我想将图像从galery上传到服务器。我成功上传图像,但我只能上传一个文件。如果我上传2个文件,第2个文件将被上传。第一个文件将不会上载。或者,如果我编辑并上传第二个图像文件,则第一个图像文件将被第二个图像文件替换 这是webservicecontroller.php $imagePath = IMAGE_PATH_FOR_TIM_THUMB.'/'.STUDY_MATERIAL_DIR.'/'; if (!empty($_POST)) { $thi
$imagePath = IMAGE_PATH_FOR_TIM_THUMB.'/'.STUDY_MATERIAL_DIR.'/';
if (!empty($_POST))
{
$this->loadModel('StudyMaterial');
if($_POST['type'] != 'delete')
{
$shift = array();
if($_POST['type'] == 'edit')
{
$shift['StudyMaterial']['id'] = $_POST['study_material_id'];
}
$shift['StudyMaterial']['user_id'] = $_POST['user_id'];
$shift['StudyMaterial']['standard_id'] = $_POST['standard_id'];
$shift['StudyMaterial']['subject_id'] = $_POST['subject_id'];
$shift['StudyMaterial']['topic_id'] = $_POST['topic_id'];
$shift['StudyMaterial']['lesson_id'] = $_POST['lesson_id'];
$shift['StudyMaterial']['name'] = $_POST['name'];
$shift['StudyMaterial']['description'] = $_POST['description'];
$this->StudyMaterial->save($shift);
$study_material_id = $this->StudyMaterial->id;
if(isset($_FILES['study_material_file']) && !empty($_FILES['study_material_file']) && ($_FILES['study_material_file']['error'] == 0))
{
$name = $_FILES['study_material_file']['name'];
$ext = substr(strrchr($name, "."), 1);
$only_name = $name . "_" . time();
$filename = 'topic_file_'.microtime(true).'.'.strtolower($ext);
$original = STUDY_MATERIAL_DIR . "/" . $filename;
$file_type = $_POST['file_type'];
if($file_type == 'video')
{
if(strtolower($ext) == 'mov')
{
$original = STUDY_MATERIAL_DIR . "/" . $filename;
@move_uploaded_file($_FILES["study_material_file"]["tmp_name"], $original);
$new_filename = $only_name. '.mp4';
$srcFile = STUDY_MATERIAL_DIR . "/" . $filename;
$destFile = STUDY_MATERIAL_DIR . "/" . $new_filename;
exec('ffmpeg -i '.$srcFile.' -f mp4 -s 320x240 '.$destFile.'');
if($_POST['type'] == 'edit')
{
$checkAlready = $this->StudyMaterial->find('first',array('conditions'=>array('StudyMaterial.id'=>$_POST['study_material_id'])));
$image = $checkAlready['StudyMaterial']['file_name'];
if($image && file_exists(WWW_ROOT.STUDY_MATERIAL_DIR.DS.$image ))
{
@unlink(WWW_ROOT.STUDY_MATERIAL_DIR.DS.$image);
}
}
$this->StudyMaterial->saveField('file_name',$filename,false);
$this->StudyMaterial->saveField('type',$file_type,false);
}
else
{
@move_uploaded_file($_FILES["study_material_file"]["tmp_name"], $original);
if($_POST['type'] == 'edit')
{
$checkAlready = $this->StudyMaterial->find('first',array('conditions'=>array('StudyMaterial.id'=>$_POST['study_material_id'])));
$image = $checkAlready['StudyMaterial']['file_name'];
if($image && file_exists(WWW_ROOT.STUDY_MATERIAL_DIR.DS.$image ))
{
@unlink(WWW_ROOT.STUDY_MATERIAL_DIR.DS.$image);
}
}
$this->StudyMaterial->saveField('file_name',$filename,false);
$this->StudyMaterial->saveField('type',$file_type,false);
}
}
else
{
@move_uploaded_file($_FILES["study_material_file"]["tmp_name"], $original);
if($_POST['type'] == 'edit')
{
$checkAlready = $this->StudyMaterial->find('first',array('conditions'=>array('StudyMaterial.id'=>$_POST['study_material_id'])));
$image = $checkAlready['StudyMaterial']['file_name'];
if($image && file_exists(WWW_ROOT.STUDY_MATERIAL_DIR.DS.$image ))
{
@unlink(WWW_ROOT.STUDY_MATERIAL_DIR.DS.$image);
}
}
$this->StudyMaterial->saveField('file_name',$filename,false);
$this->StudyMaterial->saveField('type',$file_type,false);
}
}
else
{
if($_POST['type'] == 'edit')
{
$this->StudyMaterial->id = $_POST['study_material_id'];
$this->StudyMaterial->saveField('file_name','',false);
$this->StudyMaterial->saveField('type','',false);
}
}
if($_POST['type'] == 'edit')
{
$responseData = array(
'status' => 1,
'message' => "Study Material updated successfully."
);
}
else
{
$responseData = array(
'status' => 1,
'message' => "Study Material added successfully."
);
}
}
问题出在webservice还是android?这是add_material.java
private void selectImage() {
Intent intent = new Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
intent.setType("image/*");
getActivity().startActivityForResult(Intent.createChooser(intent, "Select File"), SELECT_FILE);
}
public String getRealPathFromURI(Uri contentUri) {
String[] proj = {MediaStore.Images.Media.DATA};
Cursor cursor = getActivity().managedQuery(contentUri, proj, null, null, null);
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
服务器端出现问题,请在更新列的位置检查数据库查询。我已检查了数据库,列是正确的。如何在不替换以前图像的情况下上载文件图像?我认为每次在服务器上上载图像时都使用相同的名称。在服务器上上载图像时使用不同的名称是因为@unlink函数吗?如果(file_exists('your-filename.ext')){chmod('your-filename.ext',0755);unlink('your-filename');}移动已上载的文件($_FILES['image']['tmp_name'],'your filename');没有上载代码。那么我们能说什么呢?不清楚您是一次上载两个文件还是一个文件接着一个文件。