Php 使用facebook图表小时数检查一个地方是否开放或关闭

我正在使用facebook graph api，并获得以下JSON数据：

"hours": {
      "mon_1_open": "21:00",
      "mon_1_close": "05:00",
      "tue_1_open": "21:00",
      "tue_1_close": "05:00",
      "wed_1_open": "21:00",
      "wed_1_close": "05:00",
      "thu_1_open": "21:00",
      "thu_1_close": "05:00",
      "fri_1_open": "21:00",
      "fri_1_close": "05:00",
      "sat_1_open": "21:00",
      "sat_1_close": "05:00",
      "sun_1_open": "21:00",
      "sun_1_close": "05:00"
   }

我正在使用PHP获取我的信息，我想不出一种方法来通过上面的JSON数据检查这个（和其他地方）是打开还是关闭的

到目前为止，我没有做的只是将上述数据更改为：

星期一：21:00-05:00

星期二：21:00-05:00

等等

---

有人对如何做有什么建议吗？

这可能会给你一个想法：

<?php
$jd = cal_to_jd(CAL_GREGORIAN,date("m"),date("d"),date("Y"));
$presentday = jddayofweek($jd,1);

$opentime = "";
$closetime = "";

switch($presentday) {

    case 'Monday':
    $opentime = date("g:i a", strtotime($hour_mon_open));
    $closetime = date("g:i a", strtotime($hour_mon_close));
    break;

    case 'Tuesday':
    $opentime = date("g:i a", strtotime($hour_tue_open));
    $closetime = date("g:i a", strtotime($hour_tue_close));    
    break;

    case 'Wednesday':
    $opentime = date("g:i a", strtotime($hour_wed_open));
    $closetime = date("g:i a", strtotime($hour_wed_close));
    break;

    case 'Thursday':
    $opentime = date("g:i a", strtotime($hour_thu_open));
    $closetime = date("g:i a", strtotime($hour_thu_close));
    break;

    case 'Friday':
    $opentime = date("g:i a", strtotime($hour_fri_open));
    $closetime = date("g:i a", strtotime($hour_fri_close));
    break;

    case 'Saturday':
    $opentime = date("g:i a", strtotime($hour_sat_open));
    $closetime = date("g:i a", strtotime($hour_sat_close));
    break;

    case 'Sunday':
    $opentime = date("g:i a", strtotime($hour_sun_open));
    $closetime = date("g:i a", strtotime($hour_sun_close));
    break;

    default:
    break;        
}

$currentHours = date("g:i a", time());
$date1 = DateTime::createFromFormat('H:i a', $currentHours);
$date2 = DateTime::createFromFormat('H:i a', $opentime);
$date3 = DateTime::createFromFormat('H:i a', $closetime);

if ($date1 > $date2 && $date1 < $date3) {
    echo "Open now";
} else {
    echo "Closed now";
}
?>

希望有帮助：）