Php 合并一个数组键和另一个数组值

我有两个数组，如下所示

数组1（这是默认数组）

数组2（这是动态数组）

现在我所需要的是我想要合并数组1的值和数组2的键

仅获取在Array2中具有值的元素

删除所有其他键和值

上述示例的结果如下所示

Array
(
    [0] => pname
    [1] => minmrpprice
    //[2] => maxmrpprice(THIS DON'T SHOW BECAUSE VALUE IS EMPTY)
    [3] => unittype
    [4] => minorder
    [5] => pdetails
    [6] => status
    [7] => product_group
    [8] => specification
)

我还尝试了merge_数组，但它返回的结果如下

Array
(
    [0] => pname
    [1] => minmrpprice
    [2] => maxmrpprice
    [3] => unittype
    [4] => minorder
    [5] => pdetails
    [6] => status
    [7] => product_group
    [8] => specification
    [pname] => Designer Dress By Textilemart
    [h1] => 1
    [userid] => textilemart
    [minmrpprice] => 1212
    [maxmrpprice] => 
    [unittype] => Piece
    [minorder] => 12
    [pdetails] => adsfadf
    [_wysihtml5_mode] => 1
    [status] => 1
    [product_group] => 2
    [addGroupInput] => 
    [categories] => 2
    [9] => 299
    [10] => 84
    [11] => 71
    [12] => 45
    [specification] => 84
    [13] => 
    [submit] => Update Product
)

我不需要像这样

试试这个

Array
(
    [0] => pname
    [1] => minmrpprice
    [2] => maxmrpprice
    [3] => unittype
    [4] => minorder
    [5] => pdetails
    [6] => status
    [7] => product_group
    [8] => specification
    [pname] => Designer Dress By Textilemart
    [h1] => 1
    [userid] => textilemart
    [minmrpprice] => 1212
    [maxmrpprice] => 
    [unittype] => Piece
    [minorder] => 12
    [pdetails] => adsfadf
    [_wysihtml5_mode] => 1
    [status] => 1
    [product_group] => 2
    [addGroupInput] => 
    [categories] => 2
    [9] => 299
    [10] => 84
    [11] => 71
    [12] => 45
    [specification] => 84
    [13] => 
    [submit] => Update Product
)

循环遍历数组1，并在数组2中使用check if值

foreach($arr1 as $a){

if(!empty($arr2[$a])){

 $new[] = $a;
  }
}

print_r($new);

---

有一个函数可以完全满足您的需要，它被称为

array\u intersect\u key

，它从一个数组中删除不作为另一个数组中的键出现的所有值

您刚刚遇到的问题是，您的第一个数组没有将想要的字段作为键，而是作为值。幸运的是，有一个函数可以简单地交换这些数据，它叫做

array\u flip

<代码>数组翻转将所有值转换为键，并将其键转换为值。这只适用于

string

/

int

值

要使两个数组相交，PHP中的代码如下：

$wantedKeys = array_flip($array_one);
$result = array_intersect_key($array_two, $wantedKeys);

---

结果将是

$array\u two

的一部分，其键也出现在

$wantedKeys

数组中。

没有任何错误。请稍等片刻，您将得到一个解决方案：）您现在得到了什么？你能给我看一下预期的手术吗

$wantedKeys = array_flip($array_one);
$result = array_intersect_key($array_two, $wantedKeys);