用php为客房预订系统创建HTML表

我必须为一个房间预订系统创建一个html表，但我在尝试将数据插入单元格时遇到了麻烦。目前，我正在从数据库中获取数据（预订的开始时间和结束时间）。然后，我从一个数组中循环时间，并使用if语句将开始时间与时间数组中的时间进行比较

这就是我目前的情况： 客房预订图像

我遇到的主要问题是，在我的数据库中，如果在同一天有两个预订，它将只显示数组中的最后一个预订

    $tableStart = "<table class='table_main'><thead><tr id='table_first' class='first_last'><th class='first_last'>Time:</th>";
    $tableMid = "</tr></thead><tbody>";
    $tableEnd = "</tbody></table>";

    foreach ($newBookings as $booking) {
        $tableStart .= "<th class='first_last'>$booking[0]</th>";
    }

    foreach ($times as $time) {
        $tableMid .= "<tr class='even_row'><td class='time'>{$time['times']}</td>";
        $i = 0;
        foreach ($newBookings as $booking) {
            unset($booking[0]);
            $x = count($booking);
            if ($x > 0) {
                if ($booking[$i]['start_Time'] == $time['times']) {
                    $tableMid .= "<td class='new'>{$booking[$i]['start_Time']}</td>";
                } else if($booking[$i]['end_Time'] == $time['times']) {
                    $tableMid .= "<td class='new'>{$booking[$i]['end_Time']}</td>";
                } else {
                    $tableMid .= "<td class='new'></td>";
                }
            } else {
                $tableMid .= "<td class='new'></td>";

            }

            ++$i;
        }
    }

    $tableStart .= $tableMid;
    $tableStart .= $tableEnd;
    return $tableStart;`

---

如果我遗漏了任何内容或描述过于模糊，我深表歉意。谢谢你

对于任何看到这一点的人，我找到了一个修复方法，我使用了ADyson对阵列的建议，并重新编写了我的代码，使它现在可以正常工作。对于任何感兴趣的人，这里是我使用的代码：

public function render(): string
{

    $data = $this->tableData; //from abstract class contains table data
    $times = $this->tableTimes; //gets times
    $rooms = $this->roomNames; //gets room names
    $startTime = $times[0]['start_time']; //sets the start time
    $endTime = $times[0]['end_time']; // sets the end time
    $times = $this->setTimeArray($startTime, $endTime); //goes to function
    $newBookings = $this->setDataArray($data, $rooms); // goes to function


    $tableStart = "<table class='table_main'><thead><tr id='table_first' class='first_last'><th class='first_last'>Room:</th>";
    $tableMid = "</tr></thead><tbody>";
    $tableEnd = "</tbody></table>";

    foreach ($times as $key => $time) {
        $tableStart .= "<th class='first_last'>{$time}</th>";
    }

    foreach ($newBookings as $booking) {
        $tableMid .= "<tr class='even_row'><td class='room_Name'>{$booking['Room']}</td>";
        $x = 0;
        $e = 0;

        foreach ($times as $time) {

            if ($x == count($booking['Bookings'])) {
                $x = 0;
            }
            if ($e == count($booking['Bookings'])) {
                $e = 0;
            }

            if (count($booking['Bookings']) < 1) {
                $tableMid .= "<td class='new'></td>";
            } else if ($booking['Bookings'][$x]['start_Time'] == $time) {
                $tableMid .= "<td class='room_Booked'>{$booking['Bookings'][$x]['start_Time']}</td>";
                $x++;
            } else if ($booking['Bookings'][$e]['end_Time'] == $time) {
                $tableMid .= "<td class='room_Booked'>{$booking['Bookings'][$e]['end_Time']}</td>";
                $e++;
            } else {
                $tableMid .= "<td class='new'></td>";
            }

        }

    }

    $tableStart .= $tableMid;
    $tableStart .= $tableEnd;
    return $tableStart;
}

将房间预订数据放入一个数组中

public function setDataArray($data, $rooms)
{
    $newBookings = [];

    $x = 0;
    foreach ($rooms as $key) {
        $newBookings[$x] = array(
            'Room' => $key['room_name'], 'Bookings' => []
        );
        $y = 0;
        foreach ($data as $value) {
            if ($value['room_name'] == $newBookings[$x]['Room']) {
                $newBookings[$x]['Bookings'][$y] = [
                    'room_Name' => $value['room_name'],
                    'start_Time' => $value['requested_time'],
                    'end_Time' => $value['requested_time_end']
                ];
                $y++;
            }
        }
        $x++;
    }
    return ($newBookings);

}

---

如果屏幕截图与示例数据相匹配，则会更加清晰。此外，此数据结构：

1=>[0=>'Room 1'，1=>['Room\u Name'=>'Room 1'，'start\u Time'=>'09:30'，'end\u Time'=>'11:30'，2=>['room\u Name'=>'room 1'、'start\u Time'=>'13:00'、'end\u Time'=>'14:30']]；

似乎有点不太靠谱。您是否必须假设元素0之后的所有内容都代表预订？类似于

1=>[“room”=>'room 1'、“Bookings”=>[0=>[“房间名称”=>“房间1”，“开始时间”=>“09:30”，“结束时间”=>“11:30”]，1=>[“房间名称”=>“房间1”，“开始时间”=>“13:00”，“结束时间”=>“14:30”]]

会更符合逻辑。不要说它解决了您的问题，但可能会使数据更易于处理。还有在代码的最后一位（我假设它实际上属于第一位之前？）你定义了$roomBooking，但在另一个代码中你使用了$newBookings。它们实际上是相同的还是不同的？这有点不清楚。你是否将两个版本的代码合并在一起，或者在创建一个最小的示例或其他东西时犯了错误？是的，我只是在发布问题后才注意到它不匹配，所以我为此道歉。还有我现在设置数组的方法是，我需要0元素来获取标题的房间名称。但我可以将其分离到自己的数组中并循环使用。但是，是的，它有点粗糙，我会更改它，以便数据更易于处理。谢谢！

    public function setTimeArray($startTime, $endTime)
{
    $i = 0;
    $endTimes = strtotime($endTime);
    $endTime = date("H:i", strtotime('+30 minutes', $endTimes));
    do {
        $times[$i] = $startTime;
        $time = strtotime($startTime);
        $startTime = date("H:i", strtotime('+30 minutes', $time));
        $i++;
    } while ($startTime != $endTime);

    return ($times);
}

public function setDataArray($data, $rooms)
{
    $newBookings = [];

    $x = 0;
    foreach ($rooms as $key) {
        $newBookings[$x] = array(
            'Room' => $key['room_name'], 'Bookings' => []
        );
        $y = 0;
        foreach ($data as $value) {
            if ($value['room_name'] == $newBookings[$x]['Room']) {
                $newBookings[$x]['Bookings'][$y] = [
                    'room_Name' => $value['room_name'],
                    'start_Time' => $value['requested_time'],
                    'end_Time' => $value['requested_time_end']
                ];
                $y++;
            }
        }
        $x++;
    }
    return ($newBookings);

}