Php 需要将图像和文本发送到服务器

在我的应用程序中，我需要将图像和注释（180个字符的文本）发送到服务器

现在我可以分别发送图像和文本，但我现在需要一起发送

该方法是什么

目前我正在使用线程发送图像

// open a URL connection to the Servlet
                FileInputStream fileInputStream = new FileInputStream(
                        sourceFile);
                URL url = new URL(
                        "http://xxx.com/image.php");

                // Open a HTTP connection to the URL
                conn = (HttpURLConnection) url.openConnection();
                conn.setDoInput(true); // Allow Inputs
                conn.setDoOutput(true); // Allow Outputs
                conn.setUseCaches(false); // Don't use a Cached Copy
                conn.setRequestMethod("POST");
                conn.setRequestProperty("Connection", "Keep-Alive");
                conn.setRequestProperty("ENCTYPE", "multipart/form-data");
                conn.setRequestProperty("Content-Type",
                        "multipart/form-data;boundary=" + boundary);
                conn.setRequestProperty("uploaded_file", fileName);
                // conn.setRequestProperty("id", imei);

                dos = new DataOutputStream(conn.getOutputStream());

                dos.writeBytes(twoHyphens + boundary + lineEnd);
                dos.writeBytes("Content-Disposition: form-data; name=uploaded_file; filename="
                        + fileName + imei + lineEnd);


                dos.writeBytes(lineEnd);

                // create a buffer of maximum size
                bytesAvailable = fileInputStream.available();

                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                buffer = new byte[bufferSize];

                // read file and write it into form...
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);

                while (bytesRead > 0) {

                    dos.write(buffer, 0, bufferSize);
                    bytesAvailable = fileInputStream.available();
                    bufferSize = Math.min(bytesAvailable, maxBufferSize);
                    bytesRead = fileInputStream.read(buffer, 0, bufferSize);

                }

                // send multipart form data necesssary after file data...
                dos.writeBytes(lineEnd);
                dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

                // Responses from the server (code and message)
                serverResponseCode = conn.getResponseCode();
                String serverResponseMessage = conn.getResponseMessage();

                Log.i("uploadFile", "HTTP Response is : "
                        + serverResponseMessage + ": " + serverResponseCode);

                if (serverResponseCode == 200) {

                    runOnUiThread(new Runnable() {
                        public void run() {

                            Toast.makeText(getBaseContext(),
                                    "File Upload Complete.", Toast.LENGTH_SHORT)
                                    .show();
                            File delfile = new File(currentfile);
                            //delfile.delete();
                        }
                    });
                }

                // close the streams //
                fileInputStream.close();
                dos.flush();
                dos.close();

            } catch (MalformedURLException ex) {

                // dialog.dismiss();
                ex.printStackTrace();

                runOnUiThread(new Runnable() {
                    public void run() {
                        // messageText.setText("MalformedURLException Exception : check script url.");
                        Toast.makeText(getBaseContext(),
                                "MalformedURLException", Toast.LENGTH_SHORT)
                                .show();
                    }
                });

                Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
            } catch (Exception e) {

                // dialog.dismiss();
                e.printStackTrace();

                runOnUiThread(new Runnable() {
                    public void run() {
                        // messageText.setText("Got Exception : see logcat ");
                        Toast.makeText(getBaseContext(),
                                "upload failed Please, try after some time ",
                                Toast.LENGTH_SHORT).show();
                    }
                });
                Log.e("Upload file to server Exception",
                        "Exception : " + e.getMessage(), e);
            }
            // dialog.dismiss();
            return serverResponseCode;

        } // End else block 

用于使用简单的http post方法发送文本am

---

我需要这个为我的应用程序，我们要采取快照和键入一些东西在编辑文本框和发送

您可以使用base64编码器将图像编码为字符串（），并创建web服务将其发送到服务器。因此，在该web服务中，您可以添加多个输入。首先，您需要这个jar文件并将其导入到构建路径中

你可以这样做。考虑下面的

import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONException;
import org.json.JSONObject;

宣言：

 private List<NameValuePair> nameValuePairs;

private HttpURLConnection connection = null;
private DataOutputStream outputStream = null;
private String lineEnd = "\r\n";
private String twoHyphens = "--";
private String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;

这段代码确实工作得很好。我也检查过了。如果有任何问题，请随时联系。

试试这可能会对您有所帮助

public void WSCall(final String filePath, final String textTosend) {

        try {

            DefaultHttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://xxx.com/image.php");
            StringBody data = new StringBody(textTosend, Charset.forName(HTTP.UTF_8));
            MultiPartEntity entity = new MultiPartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
            entity.addPart("uploaded_file", new FileBody(new File(filePath), "image/png"));
            entity.addPart("text", data);
            httppost.setEntity(entity);
            HttpResponse WSresponse = httpclient.execute(httppost);
        } catch (Throwable e) {

        }

    }

---

您应该将Httpclient与HttpPost和MultipartEntity一起使用，以发送MIME类型的数据以及text.am使用Httpclient、httpcore、mime4j、apachehttpclient jar文件，但多部分实体仍然存在错误，

outputStream.writeBytes（“内容处理：表单数据；名称=”您的参数名称\“+lineEnd）；outputStream.writeBytes（lineEnd）；outputStream.writeBytes（“您的值”）粘贴结束是文件名。我正在向服务器发送文件和文本<代码>outputStream.writeBytes（“内容处置：表单数据；名称=\“您的参数名称\”+lineEnd）；outputStream.writeBytes（lineEnd）；writeBytes（“在此处添加您的值”）你能解释一下吗，第二个参数添加到哪里了？写字节（两个连字符+边界+行结束）的含义是什么？从哪里开始，从哪里结束？你能给我解释一下吗。
public void WSCall(final String filePath, final String textTosend) {

        try {

            DefaultHttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://xxx.com/image.php");
            StringBody data = new StringBody(textTosend, Charset.forName(HTTP.UTF_8));
            MultiPartEntity entity = new MultiPartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
            entity.addPart("uploaded_file", new FileBody(new File(filePath), "image/png"));
            entity.addPart("text", data);
            httppost.setEntity(entity);
            HttpResponse WSresponse = httpclient.execute(httppost);
        } catch (Throwable e) {

        }

    }