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如何在PHP中解析JSON数组并在HTML表中显示？

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如何在PHP中解析JSON数组并在HTML表中显示？,php,arrays,json,curl,php-curl,Php,Arrays,Json,Curl,Php Curl,我需要在PHP中解析JSON数组响应，并在HTML表中回显这些值。我对PHP-JSON非常陌生，我想不出一种方法来做到这一点 $curl_response = curl_exec($curl); echo $curl_response . PHP_EOL; JSON数组响应： { "employees": [ { "emp_id":101, "name":&quo

我需要在PHP中解析JSON数组响应，并在HTML表中回显这些值。我对PHP-JSON非常陌生，我想不出一种方法来做到这一点

$curl_response = curl_exec($curl);
echo $curl_response . PHP_EOL;
JSON数组响应：

{
    "employees": [
        {
            "emp_id":101,
            "name":"Christ Joseph",
            "email":"emp101@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":0,
                    "grade":A
                }
            ]
        },
        {
            "emp_id":102,
            "name":"Paolo Jobh",
            "email":"emp102@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":100,
                    "grade":B
                }
            ]
        },
        {
            "emp_id":103,
            "name":"Subo Paul",
            "email":"emp103@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":15,
                    "grade":B
                }
            ]
        },
    ]
}

$json = json_decode($curl_response, true);

echo "<table border='1' width='50%' align='center'>";
foreach($json['employees'] as $data)
{
   if($json['employees'][0]['attendance']['days_present'] == 0) {
     //exclude the employees whose days_present is 0
   } else { 
   echo "<tr>";
   echo "<td>$json['employees']['emp_id']</td>";
   echo "<td>$json['employees']['email']</td>";
   echo "<td>$json['employees']['days_present']</td>";
   echo "<td>$json['employees'][0]['attendace']['grade']</td>";
   echo "</tr>";
  }
}

(empty table)

<table border="1" width="50%" align="center">
<!-- Display the JSON array response here -->
<tr>
  <td>102</td>
  <td>emp102@example.com</td>
  <td>100</td>
  <td>B</td>
</tr>
<tr>
  <td>103</td>
  <td>emp103@example.com</td>
  <td>15</td>
  <td>B</td>
</tr>
PHP脚本：

{
    "employees": [
        {
            "emp_id":101,
            "name":"Christ Joseph",
            "email":"emp101@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":0,
                    "grade":A
                }
            ]
        },
        {
            "emp_id":102,
            "name":"Paolo Jobh",
            "email":"emp102@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":100,
                    "grade":B
                }
            ]
        },
        {
            "emp_id":103,
            "name":"Subo Paul",
            "email":"emp103@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":15,
                    "grade":B
                }
            ]
        },
    ]
}

$json = json_decode($curl_response, true);

echo "<table border='1' width='50%' align='center'>";
foreach($json['employees'] as $data)
{
   if($json['employees'][0]['attendance']['days_present'] == 0) {
     //exclude the employees whose days_present is 0
   } else { 
   echo "<tr>";
   echo "<td>$json['employees']['emp_id']</td>";
   echo "<td>$json['employees']['email']</td>";
   echo "<td>$json['employees']['days_present']</td>";
   echo "<td>$json['employees'][0]['attendace']['grade']</td>";
   echo "</tr>";
  }
}

(empty table)

<table border="1" width="50%" align="center">
<!-- Display the JSON array response here -->
<tr>
  <td>102</td>
  <td>emp102@example.com</td>
  <td>100</td>
  <td>B</td>
</tr>
<tr>
  <td>103</td>
  <td>emp103@example.com</td>
  <td>15</td>
  <td>B</td>
</tr>
预期输出：

{
    "employees": [
        {
            "emp_id":101,
            "name":"Christ Joseph",
            "email":"emp101@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":0,
                    "grade":A
                }
            ]
        },
        {
            "emp_id":102,
            "name":"Paolo Jobh",
            "email":"emp102@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":100,
                    "grade":B
                }
            ]
        },
        {
            "emp_id":103,
            "name":"Subo Paul",
            "email":"emp103@example.com",
            "attendance": [
                {
                    "last_day_present":"13-05-2021",
                    "days_present":15,
                    "grade":B
                }
            ]
        },
    ]
}

$json = json_decode($curl_response, true);

echo "<table border='1' width='50%' align='center'>";
foreach($json['employees'] as $data)
{
   if($json['employees'][0]['attendance']['days_present'] == 0) {
     //exclude the employees whose days_present is 0
   } else { 
   echo "<tr>";
   echo "<td>$json['employees']['emp_id']</td>";
   echo "<td>$json['employees']['email']</td>";
   echo "<td>$json['employees']['days_present']</td>";
   echo "<td>$json['employees'][0]['attendace']['grade']</td>";
   echo "</tr>";
  }
}

(empty table)

<table border="1" width="50%" align="center">
<!-- Display the JSON array response here -->
<tr>
  <td>102</td>
  <td>emp102@example.com</td>
  <td>100</td>
  <td>B</td>
</tr>
<tr>
  <td>103</td>
  <td>emp103@example.com</td>
  <td>15</td>
  <td>B</td>
</tr>


102
emp102@example.com
100
B
103
emp103@example.com
15
B
有人，请帮我找出剧本的毛病。有没有更好的方法可以更快地执行脚本并减少流量负载？

您正在使用的
foreach/as
循环将
$json['employees']
数组的每个元素放入一个名为
$data
的变量中。您需要像这样调整代码

改变

foreach($json['employees'] as $data)
{
   if($json['employees'][0]['attendance']['days_present'] == 0) {
     //exclude the employees whose days_present is 0
   } else { 
   echo "<tr>";
   echo "<td>$json['employees']['emp_id']</td>";
   echo "<td>$json['employees']['email']</td>";
   echo "<td>$json['employees']['days_present']</td>";
   echo "<td>$json['employees'][0]['attendace']['grade']</td>";
   echo "</tr>";
  }
}

foreach（$json['employees']作为$data）
{
如果（$json['employees'][0]['Attention']['days_present']]==0）{
//排除当前天数为0的员工
}否则{
回声“；
echo“$json['employees']['emp_id']”；
echo“$json['employees']['email']”；
echo“$json['employees']['days_present']”；
echo“$json['employees'][0]['attendace']['grade']”；
回声“；
}
}
到

foreach（$json['employees']作为$data）
{
如果（$data['ATSINGENT'][0]['days\U present']==0）{
//排除当前天数为0的员工
}否则{
回声“；
echo“$data['emp_id']”；
回显“$data['email']”；
echo“$data['attention'][0]['days_present']”；
echo“$data['attention'][0]['grade']”；
回声“；
}
}
非常简单的问题；我重写了您提供的整个json数组，并将其编码为json，以查看正确的结构，如下所示：

{
    "employees": [
        {
            "emp_id": 101,
            "name": "Christ Joseph",
            "email": "emp101@example.com",
            "attendance": {
                "last_day_present": "13-05-2021",
                "days_present": 0,
                "grade": "A"
            }
        },
        {
            "emp_id": 102,
            "name": "Paolo Jobh",
            "email": "emp102@example.com",
            "attendance": {
                "last_day_present": "13-05-2021",
                "days_present": 100,
                "grade": "B"
            }
        },
        {
            "emp_id": 103,
            "name": "Subo Paul",
            "email": "emp103@example.com",
            "attendance": {
                "last_day_present": "13-05-2021",
                "days_present": 15,
                "grade": "B"
            }
        }
    ]
}
1st:您的
[“出勤”][“成绩”]
值周围没有引号。任何包含非字母数字字符或字母字符的内容都需要引用。只有数值可以不加引号（如果我错了，请纠正我，但我很确定这是怎么回事）

2nd:在
[“考勤”]
值的周围有方括号，这将它放在一个未命名的维度中，这实际上是不必要的，只是使得检索它有点困难

3rd:底部最后一个逗号如下：
}，
是您的
json\u解码没有得到任何响应的另一个原因。删除最后一个毫无意义的逗号，并至少执行第一步，它应该会起作用

下面是您的JSON数组，指出了错误：


{
        "employees": [
            {
                "emp_id":101,
                "name":"Christ Joseph",
                "email":"emp101@example.com",
                "attendance": [ # <---------- 2nd Problem 
                    {
                        "last_day_present":"13-05-2021",
                        "days_present":0,
                        "grade":A # <---------- 1st Problem
                    }
                ] # <---------- 2nd Problem
            },
            {
                "emp_id":102,
                "name":"Paolo Jobh",
                "email":"emp102@example.com",
                "attendance": [ # <---------- 2nd Problem
                    {
                        "last_day_present":"13-05-2021",
                        "days_present":100,
                        "grade":B # <---------- 1st Problem
                    }
                ] # <---------- 2nd Problem
            },
            {
                "emp_id":103,
                "name":"Subo Paul",
                "email":"emp103@example.com",
                "attendance": [ # <---------- 2nd Problem
                    {
                        "last_day_present":"13-05-2021",
                        "days_present":15,
                        "grade":B # <---------- 1st Problem
                    }
                ] # <---------- 2nd Problem
            }, # <---------- 3rd Problem
        ]
    }



{
“雇员”：[
{
“emp_id”：101，
“姓名”：“基督约瑟夫”，
“电子邮件”：emp101@example.com",

“出席情况”：[#哈哈，我甚至没有走那么远，但这确实是另一个问题：P我试图测试他的一些代码，但我甚至无法解码他提供的JSON，似乎是无效的。按照你的答案。但最后两列显示为空。我已经修复了最后两列的代码，尽管@Crimin4L说，我怀疑它不会起任何作用是的，因为JSON有问题。我调整并批准了@Crimin4L的编辑。对数组变量的连接而不是插值考虑得很好。我将数组引用保留在
$data['Attention']
由于原始海报的“JSON”以数组形式显示“出席”。哈哈，谢谢@WillWalsh，我想知道你为什么要把它们放在
[0]
“在那里，但后来它点击了，我意识到了原因；我在回答中提到的括号只是一个未命名的维度lolol1st-有点正确。PHP将处理带有索引的关联数组，但周围没有引号，但它会抛出警告。最好的做法是包含引号。