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Php 为一个人而不是几个人选择返回结果的语句_Php_Codeigniter_Activerecord - Fatal编程技术网

Php 为一个人而不是几个人选择返回结果的语句

Php 为一个人而不是几个人选择返回结果的语句,php,codeigniter,activerecord,Php,Codeigniter,Activerecord,当有多个姓氏相同时,搜索名称将返回一个结果。它可能是foreach循环,但我认为它是activerecord语句 模型 看法 if(isset($user)){ foreach($user as$res){ echo“employee id=”.$res['emp_no'];?>您的返回值在for循环中。将返回语句从foreach循环中取出 foreach ($result->result() as $row ) { $entry = array(); $entry

当有多个姓氏相同时,搜索名称将返回一个结果。它可能是foreach循环,但我认为它是activerecord语句

模型

看法

if(isset($user)){
foreach($user as$res){

echo“employee id=”.$res['emp_no'];?>




您的
返回值在
for
循环中。

将返回语句从foreach循环中取出

foreach ($result->result() as $row )
    {
    $entry = array();
    $entry['emp_no'] = $row->emp_no;        
    $entry['first_name'] = $row->first_name;
    $entry['last_name'] = $row->last_name;      
    $entry['title'] = $row->title;
    $entry['dept_no'] = $row->dept_no;

    $data[] = $entry;



}
 return $data;

真不敢相信我忽略了这一点,塔克斯。
if (isset($user)) {
foreach ($user as $res) {

echo "employee id =" .$res['emp_no']; ?> <br> <?php
echo "first name = " .$res['first_name']; ?> <br> <?php
echo "last name = " .$res['last_name']; ?> <br> <?php
echo "title = " .$res['title']; ?> <br> <?php
echo "department no = " .$res['dept_no']; ?> <br><br> <?php  
foreach ($result->result() as $row )
    {
    $entry = array();
    $entry['emp_no'] = $row->emp_no;        
    $entry['first_name'] = $row->first_name;
    $entry['last_name'] = $row->last_name;      
    $entry['title'] = $row->title;
    $entry['dept_no'] = $row->dept_no;

    $data[] = $entry;



}
 return $data;