Php 如何在移动图像时动态创建文件夹?
我使用的是laravel 5.3 我的代码可以像这样移动图像:Php 如何在移动图像时动态创建文件夹?,php,laravel,file-upload,laravel-5.3,image-uploading,Php,Laravel,File Upload,Laravel 5.3,Image Uploading,我使用的是laravel 5.3 我的代码可以像这样移动图像: private function savePhoto($photos, $id) { foreach($photos as $key => $photo) { $temp = storage_path() . DIRECTORY_SEPARATOR . 'temp' . DIRECTORY_SEPARATOR . $photo['name']; $destinationPath = pu
private function savePhoto($photos, $id)
{
foreach($photos as $key => $photo) {
$temp = storage_path() . DIRECTORY_SEPARATOR . 'temp' . DIRECTORY_SEPARATOR . $photo['name'];
$destinationPath = public_path() . DIRECTORY_SEPARATOR . 'img'. DIRECTORY_SEPARATOR .'products'.DIRECTORY_SEPARATOR.$id.DIRECTORY_SEPARATOR.$photo['name'];
if( rename( $temp , $destinationPath )){
echo 'moved!';
}
else {
echo 'failed';
}
}
}
Array
(
[0] => Array
(
[id] => 1
[name] => vYcHWLXpwhC9WfXd4XCB2emg83WMtWHphyUBq9MV.jpeg
)
[1] => Array
(
[id] => 2
[name] => 1STr51oF8cunSsNEJZyS9upI0hNHYMXjLCCSNonz.jpeg
)
)
执行时存在如下错误:
private function savePhoto($photos, $id)
{
foreach($photos as $key => $photo) {
$temp = storage_path() . DIRECTORY_SEPARATOR . 'temp' . DIRECTORY_SEPARATOR . $photo['name'];
$destinationPath = public_path() . DIRECTORY_SEPARATOR . 'img'. DIRECTORY_SEPARATOR .'products'.DIRECTORY_SEPARATOR.$id.DIRECTORY_SEPARATOR.$photo['name'];
if( rename( $temp , $destinationPath )){
echo 'moved!';
}
else {
echo 'failed';
}
}
}
Array
(
[0] => Array
(
[id] => 1
[name] => vYcHWLXpwhC9WfXd4XCB2emg83WMtWHphyUBq9MV.jpeg
)
[1] => Array
(
[id] => 2
[name] => 1STr51oF8cunSsNEJZyS9upI0hNHYMXjLCCSNonz.jpeg
)
)
重命名(C:\xampp\htdocs\myshop\storage\temp\NOTFCjMipXwFhBICo1tj6VXP5Qhv92Fg1kmawcUd.jpeg,C:\xampp\htdocs\myshop\public\img\products\77\NOTFCjMipXwFhBICo1tj6VXP5Qhv92Fg1kmawcUd.jpeg):
系统找不到指定的路径。(代码:3)
我认为发生错误是因为$id文件夹是动态生成的。$id文件夹取决于参数id。如果参数id=77,则其格式如下:
C:\xampp\htdocs\myshop\public\img\products\77\NOTFCjMipXwFhBICo1tj6VXP5Qhv92Fg1kmawcUd.jpeg
因此发生错误是因为文件夹77尚不存在
如何在移动图像之前先创建文件夹77(这是动态生成的)
更新
$photos的示例阵列结果如下:
private function savePhoto($photos, $id)
{
foreach($photos as $key => $photo) {
$temp = storage_path() . DIRECTORY_SEPARATOR . 'temp' . DIRECTORY_SEPARATOR . $photo['name'];
$destinationPath = public_path() . DIRECTORY_SEPARATOR . 'img'. DIRECTORY_SEPARATOR .'products'.DIRECTORY_SEPARATOR.$id.DIRECTORY_SEPARATOR.$photo['name'];
if( rename( $temp , $destinationPath )){
echo 'moved!';
}
else {
echo 'failed';
}
}
}
Array
(
[0] => Array
(
[id] => 1
[name] => vYcHWLXpwhC9WfXd4XCB2emg83WMtWHphyUBq9MV.jpeg
)
[1] => Array
(
[id] => 2
[name] => 1STr51oF8cunSsNEJZyS9upI0hNHYMXjLCCSNonz.jpeg
)
)
使用
我已经试过了。但都是一样的。你能完全更新你的答案吗?所以它可以适应我的case@samuel,更新了我的回答存在如下错误:
mkdir():文件存在
。如果临时文件夹中有2个图像,则只移动了1个图像。应移动2个图像is_dir()
check。这将消除错误。请立即尝试关于“2张图片”问题:看起来它们的名称是相同的。