Plotly 具有特定颜色的多曲面打印图例

以

plot\u ly

函数为例：

library("plotly")
z <- c(
  c(8.83,8.89,8.81,8.87,8.9,8.87),
  c(8.89,8.94,8.85,8.94,8.96,8.92),
  c(8.84,8.9,8.82,8.92,8.93,8.91),
  c(8.79,8.85,8.79,8.9,8.94,8.92),
  c(8.79,8.88,8.81,8.9,8.95,8.92),
  c(8.8,8.82,8.78,8.91,8.94,8.92),
  c(8.75,8.78,8.77,8.91,8.95,8.92),
  c(8.8,8.8,8.77,8.91,8.95,8.94),
  c(8.74,8.81,8.76,8.93,8.98,8.99),
  c(8.89,8.99,8.92,9.1,9.13,9.11),
  c(8.97,8.97,8.91,9.09,9.11,9.11),
  c(9.04,9.08,9.05,9.25,9.28,9.27),
  c(9,9.01,9,9.2,9.23,9.2),
  c(8.99,8.99,8.98,9.18,9.2,9.19),
  c(8.93,8.97,8.97,9.18,9.2,9.18)
)
dim(z) <- c(15,6)
z2 <- z + 1

fig <- plot_ly(showscale = FALSE)
fig <- fig %>% add_surface(z = ~z, colorscale = list(c(0,1),c("rgb(107,184,255)","rgb(0,90,124)")))
fig <- fig %>% add_surface(z = ~z2, colorscale = list(c(0,1),c("rgb(255,107,184)","rgb(128,0,64)")))

library（“plotly”）
z你在找这个吗：

  plot_ly(showscale = FALSE, showlegend = TRUE) %>% 
  add_surface(z = ~z, name = "Color Blue", colorscale = list(c(0,1),c("rgb(107,184,255)","rgb(0,90,124)"))) %>% 
  add_surface(z = ~z2, name = "Color Red", colorscale = list(c(0,1),c("rgb(255,107,184)","rgb(128,0,64)")))

如果使用
showscale=TRUE
则有两个图例。这就是你想要的吗。否则，你能更具体一点吗？在这种情况下，出现的图例有一系列的颜色，尽管我的每个表面只有一种颜色。我想要一个只说紫色是
a
，黄色是
b
的图例@姆拉沃伊