PLSQL-如何检查和输入是一个数字

如何更改此代码以检查团队ID和输入是否为数字？ 如果是-打开光标，如果不是，请打印一个数字

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最小值为1，最大值为团队ID的最大数量？还是仅仅是一个数字

要处理替换变量，您需要将它们括在引号中，并将它们视为字符串

例如，这可能是一种做您需要的事情的方法：

DECLARE
  TEAM_ID NUMBER := &INPUT;
  CURSOR C_WORKER IS
  SELECT FIRST_NAME, LAST_NAME
  FROM EMPLOYEES
  WHERE DEPARTMENT_ID = TEAM_ID;
  V_LAST_NAME EMPLOYEES.LAST_NAME%TYPE;
  V_FIRST_NAME EMPLOYEES.FIRST_NAME%TYPE;
BEGIN
  OPEN C_WORKER;
    LOOP
      FETCH C_WORKER INTO V_LAST_NAME, V_FIRST_NAME;
      EXIT WHEN C_WORKER%NOTFOUND;
      DBMS_OUTPUT.PUT_LINE(V_LAST_NAME || ' ' || V_FIRST_NAME);
    END LOOP;
  CLOSE C_WORKER;
END;

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您接受哪种类型的数字，以及采用哪种格式？例如，带有千位分隔符的数字是否有效？还有一个否定的。。。请尝试更好地定义您需要的支票以获得一些help@Aleksej我编辑这篇文章。好吗？还不清楚“1000”是否应该算作数字。

declare
    -- define a varchar2 variable to host your variable; notice the quotes
    vStringInput        varchar2(10) := '&input';
    vNumInput           number;
    vVal                number;
    -- define a parametric cursor, to avoid references to variables
    cursor cur(num number) is select num from dual;
begin
    -- try to convert the string to a number
    begin
        vNumInput :=  to_number(vStringInput);
    exception
        when others then 
            vNumInput := null;
    end;
    --
    -- check the values, to understand if it is a number ( vNumInput NULL or NOT NULL)
    -- and, in case it's a number, if it suits your criteria
    case
        when vNumInput is null then 
            dbms_output.put_line('not a number');
        when vNumInput < 1 then 
            dbms_output.put_line('less than 1');
        -- whatever check you need on the numeric value
        else
            -- if the value is ok, open the cursor
            open cur(vNumInput); 
            loop
                fetch cur into vVal;                
                exit when cur%NOTFOUND;
                dbms_output.put_line('value from cursor: ' || vVal);
            end loop;            
    end case;    
end;
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