Plsql 使用having count的PL/SQL更新率

你好，我是pl/sql的新手

我需要更新所有少于5名员工到500名员工的项目的每小时费率

这是我写的代码，但它更新了所有员工

set serveroutput on

declare
  cursor rate_cur is
  select * from project
  for update of rate_per_hour;
begin
  for rate_rec IN rate_cur
  loop
    update project
    set rate_per_hour=500
    where current of rate_cur;
  end loop;

end;

这是我的桌子：

CREATE TABLE employee(
empid number(5),
empname varchar(20),
address varchar(20),
no_of_dependents number(5),
deptno number(5),
CONSTRAINT EMPLOYEE_PKEY PRIMARY KEY(empid),
CONSTRAINT EMPLOYEE_FKEY FOREIGN KEY(deptno) REFERENCES department(deptno));

CREATE TABLE project(
projectno number(5),
location varchar(20),
incharge number(5),
rate_per_hour number(5),
CONSTRAINT PROJECT_PKEY PRIMARY KEY(projectno),
CONSTRAINT PROJECT_FKEY FOREIGN KEY(incharge) REFERENCES employee(empid));

CREATE TABLE assignment(
empid number(5),
projectid number(5),
hours number(5),
CONSTRAINT ASSIGNMENT_FKEY FOREIGN KEY(empid) REFERENCES employee(empid),
CONSTRAINT ASSIGNEMNT_FKEY2 FOREIGN KEY(projectid) REFERENCES project(projectno));




  Please suggest a solution

---

它会更新所有项目，因为您正在无限制地选择所有项目。您可以将光标更改为以下内容：

declare
  cursor RATE_CUR is
    select     P.PROJECTNO, count(*) as EMP_CNT
    from       PROJECT P
               join ASSIGNMENT A
                 on A.PROJECTID = P.PROJECTNO
    group by   PROJECTNO
    having     count(*) < 5;
begin
  for RATE_REC in RATE_CUR loop
    update PROJECT
    set    RATE_PER_HOUR = 500
    where  PROJECTNO = RATE_REC.PROJECTNO;
  end loop;
end;

---

我在其他论坛上找到了帮助！这是密码

update project
set    rate_per_hour = 500
where  projectno IN 
    (select projectid
     from assignment
     group by projectid
     having count(distinct empid) <5);

---

不允许更新此查询表达式的FOR。即使删除更新并更改行|其中projectno=rate\u cur.projectno |到|其中prokectno=rate\u rec.projectno | rate\u cur.PROJEC\u TNO:无效标识我编辑它以修复这些拼写错误。您从另一个论坛获得的解决方案更好，因为它只是纯SQL，我的目标是修复您的PL/SQL。