Postgresql 按子级排序的jsonb_路径_查询

我有一个嵌套的json结构

{
  "feed": {
    "3": {
       "id1": {
          "id": "activity-1",
          "created": 1469905513973,
          "verb": "added recipe 1"
       },
       "id2": {
          "id": "activity-2",
          "created": 1470013085119,
          "verb": "added recipe 2"
       },
       "id3": {
          "id": "activity-3",
          "created": 1472341861543,
          "verb": "added recipe 3"
       }
    }
  }
}

我想选择

/feed/3

中的所有内容，并按创建的

订购

我一直无法理解正确的语法

SELECT jsonb_path_query(
    '{ "feed": { "3": { "id1": { "id": "activity-1", "created": 1469905513973, "verb": "added recipe 1" }, "id2": { "id": "activity-2", "created": 1470013085119, "verb": "added recipe 2" }, "id3": { "id": "activity-3", "created": 1472341861543, "verb": "added recipe 3" } } } }',
     '$."feed"."3".*')
 order by "created" desc;

此版本给了我一个
错误：列“created”不存在

如果没有ORDERBY子句，则输出如下

# SELECT jsonb_path_query('{ "feed": { "3": { "id1": { "id": "activity-1", "created": 1469905513973, "verb": "added recipe 1" }, "id2": { "id": "activity-2", "created": 1470013085119, "verb": "added recipe 2" }, "id3": { "id": "activity-3", "created": 1472341861543, "verb": "added recipe 3" } } } }', '$."feed"."3".*');
                             jsonb_path_query                             
--------------------------------------------------------------------------
 {"id": "activity-1", "verb": "added recipe 1", "created": 1469905513973}
 {"id": "activity-2", "verb": "added recipe 2", "created": 1470013085119}
 {"id": "activity-3", "verb": "added recipe 3", "created": 1472341861543}
(3 rows)

我很确定这是jsonb_path_查询返回集合的副作用，但我不知道如何处理它。谢谢你的帮助
 您的结果不包含名为
created
的列，只包含名为
jsonb\u path\u query
的列，该列包含JSON值

您需要从JSON中提取数字，以便能够对其进行排序。还建议在FROM子句中使用set返回函数：

SELECT *
FROM jsonb_path_query('{...}', '$."feed"."3".*') as t(item)
order by (item ->> 'created')::bigint desc;