Postgresql 不可能Postgres环

我有一个Postgres循环：

CREATE OR REPLACE FUNCTIOn insertIds() RETURNS int4 AS '
    DECLARE r RECORD;

    BEGIN
        FOR r IN SELECT id_client FROM client WHERE id_isigeo_util =153 LOOP
               INSERT INTO temps_production VALUES (nextval('temps_production_id_seq'::regclass),(SELECT max(id_livrable) FROM livrable),0,r.id_client,0,now(),0,now(),now());
        END LOOP;
    return 1;
    END;
    ' LANGUAGE plpgsql;
SELECT insertIds() as output;

这给了我一个错误：

 ERROR:  syntax error at or near "temps_production_id_seq"
LINE 6: ...    INSERT INTO temps_production VALUES (nextval('temps_prod...
                                                             ^
********** Erreur **********

ERROR: syntax error at or near "temps_production_id_seq"
État SQL :42601
Caractère : 228

我想将select中包含的每个ID复制到temps_产品的一行中，序列号位于第一个位置，但它显示错误，它似乎不理解nextval，但我需要它，因为它是序列号

编辑：关于SELECT maxid_livrable FROM livrable，我知道它不好，因为可能会出现并发问题，但我尝试从上一次SQL插入中获取返回的变量，它给了我一个错误：

 INSERT INTO livrable VALUES (nextval('id_livrable_fid_seq'::regclass),'',now(),now(),'',0,0,0,0,0,0,0,0,0,0,0,0,0,(SELECT max(id_passation)+1 FROM passation),0) RETURNING id_livrable;

这就是我的循环的外观，之后请注意id_livarable，它应该是来自上一个sql插入的变量…：

        CREATE OR REPLACE FUNCTIOn insertIds() RETURNS int4 
        AS 
        $body$ --<< start of the "dollar quoting"
        DECLARE r RECORD;

        BEGIN
            FOR r IN SELECT id_client FROM client WHERE id_isigeo_util =153 LOOP
               INSERT INTO temps_production VALUES (nextval('temps_production_id_seq'::regclass),id_livrable,r.id_client,0,0,now(),0,now(),now());
            END LOOP;
        return 1;
        END;
        $body$ --< end of the "dollar quoting"
        LANGUAGE plpgsql;

        SELECT insertIds() as output;

我试过这个：

    DECLARE myid livrable.id_livrable%TYPE;
INSERT INTO livrable VALUES (nextval('id_livrable_fid_seq'::regclass),'',now(),now(),'',0,0,0,0,0,0,0,0,0,0,0,0,0,(SELECT max(id_passation)+1 FROM passation),0) RETURNING id_livrable INTO myid;

但错误是：

 ERROR:  syntax error at or near "livrable"
LINE 2: DECLARE myid livrable.id_livrable%TYPE;
                     ^
********** Erreur **********

ERROR: syntax error at or near "livrable"
État SQL :42601
Caractère : 15

编辑2：它最终是这样工作的，案件结束了谢谢你我也会做你提供的代码：

CREATE OR REPLACE FUNCTIOn insertIds() RETURNS int4 
        AS 
        $body$ --<< start of the "dollar quoting"
        DECLARE r RECORD;
        DECLARE myid livrable.id_livrable%TYPE;
        BEGIN
        INSERT INTO livrable VALUES (nextval('id_livrable_fid_seq'::regclass),'',now(),now(),'',0,0,0,0,0,0,0,0,0,0,0,0,0,(SELECT max(id_passation)+1 FROM passation),0) RETURNING id_livrable INTO myid;
            FOR r IN SELECT id_client FROM client WHERE id_isigeo_util =153 LOOP
               INSERT INTO temps_production VALUES (nextval('temps_production_id_seq'::regclass),myid,r.id_client,0,0,now(),0,now(),now());
            END LOOP;
        return 1;
        END;
        $body$ --< end of the "dollar quoting"
        LANGUAGE plpgsql;

        SELECT insertIds() as output;

---

您的问题是嵌套的单引号

为避免该使用出现问题，请执行以下操作：

在insert语句中显式声明列也是一种很好的编码方式：

insert into temps_production (id, ....) 
select ...

---

好的，谢谢你，我正在尝试，但是插入像这样单独工作。如果你使用序列，为什么要使用select max？@nick:请查看我的编辑。您的函数是不必要的complexOk，是的，我同意，selectmax不正确，但我试图从以前的SQL插入中获取名为“id_livarable”的返回变量，但循环随后不接受或识别它。插入可能返回多个id，但是你的函数被定义为returns int，所以你不能从该函数返回一个以上的值。我编辑了我的消息，你有时使用返回变量吗？我无法将返回的变量注入到上一个INSERT查询的循环中，谢谢

CREATE OR REPLACE FUNCTIOn insertIds() RETURNS int4 
AS 
$body$ --<< start of the "dollar quoting"
DECLARE r RECORD;

BEGIN
    FOR r IN SELECT id_client FROM client WHERE id_isigeo_util =153 LOOP
           INSERT INTO temps_production VALUES (nextval('temps_production_id_seq'::regclass),(SELECT max(id_livrable)+1 FROM livrable),0,r.id_client,0,now(),0,now(),now());
    END LOOP;
return 1;
END;
$body$ --< end of the "dollar quoting"
LANGUAGE plpgsql;

SELECT insertIds() as output;

CREATE OR REPLACE FUNCTIOn insertIds() RETURNS int4 
AS 
$body$
DECLARE 
  l_count bigint;

BEGIN
   -- ATTENTION: 
   -- this will not work correctly with concurrent transactions on the livrable table!
   SELECT max(id_livrable)+1 
      into l_count
   FROM livrable;

   INSERT INTO temps_production 
   select nextval('temps_production_id_seq'),
          l_count,
          0, 
          c.id_client,
          0,
          now(),
          0,
          now(),
          now()
    FROM client c
    WHERE id_isigeo_util = 153;

    return 1;
END;
$body$
LANGUAGE plpgsql;

SELECT insertIds() as output;

insert into temps_production (id, ....) 
select ...