Postgresql 在另一个查询的选择中查询jsonb数组
我有一个带有列favorites的用户表,该列是jsonbPostgresql 在另一个查询的选择中查询jsonb数组,postgresql,postgresql-10,Postgresql,Postgresql 10,我有一个带有列favorites的用户表,该列是jsonb favorites: [ { "id_doc:": 9, "type": "post" }, { "id_doc": 10, "type": "post" }
favorites:
[
{
"id_doc:": 9,
"type": "post"
},
{
"id_doc": 10,
"type": "post"
}
]
我还有另外一个表POST,我想按id进行查询,这个id必须在favorites用户的id\u doc字段中
select * from posts where id in (select favorites -> id_doc from users )
这是模式
CREATE TABLE dev.users
(
id integer NOT NULL GENERATED BY DEFAULT AS IDENTITY ( INCREMENT 1 START 1 MINVALUE 1 MAXVALUE 2147483647 CACHE 1 ),
firstname character varying COLLATE pg_catalog."default" NOT NULL,
lastname character varying COLLATE pg_catalog."default" NOT NULL,
email character varying COLLATE pg_catalog."default" NOT NULL,
password character varying COLLATE pg_catalog."default" NOT NULL,
favorites jsonb[],
CONSTRAINT users_pkey PRIMARY KEY (id),
CONSTRAINT email_key UNIQUE (email)
)
WITH (
OIDS = FALSE
)
TABLESPACE pg_default;
ALTER TABLE dev.users
OWNER to postgres;
CREATE TABLE dev.posts
(
id integer NOT NULL DEFAULT nextval('dev.posts_id_seq'::regclass),
title character varying COLLATE pg_catalog."default" NOT NULL,
userid integer NOT NULL,
description character varying COLLATE pg_catalog."default" NOT NULL,
CONSTRAINT posts_pkey PRIMARY KEY (id)
)
WITH (
OIDS = FALSE
)
TABLESPACE pg_default;
ALTER TABLE dev.posts
OWNER to postgres;
我该怎么做?
谢谢还有其他方法可以做到这一点,但为了清晰起见,我更喜欢使用CTE。请让我知道在评论中,如果你有什么问题,这是什么
with elements as (
select jsonb_array_elements(favorites) as favitem
from users
), fav_ids as (
select distinct (favitem->>'id_doc')::int as id_doc
from elements
)
select p.*
from posts p
join fav_ids f on f.id_doc = p.id
;
更新
由于列被定义为jsonb[]
而不是json
,因此我们需要unest()
而不是jsonb\u array\u elements()
:
有其他方法可以实现这一点,但为了清晰起见,我更喜欢使用CTE。请让我知道在评论中,如果你有什么问题,这是什么
with elements as (
select jsonb_array_elements(favorites) as favitem
from users
), fav_ids as (
select distinct (favitem->>'id_doc')::int as id_doc
from elements
)
select p.*
from posts p
join fav_ids f on f.id_doc = p.id
;
更新
由于列被定义为jsonb[]
而不是json
,因此我们需要unest()
而不是jsonb\u array\u elements()
:
我有个错误。jsonb_数组_元素(jsonb[])没有exist@simo9900请更新您的问题以显示表架构。我们必须以不同于
jsonb
的方式对待jsonb[]
列。我将更新我的答案。我有一个错误。jsonb_数组_元素(jsonb[])没有exist@simo9900请更新您的问题以显示表架构。我们必须以不同于jsonb
的方式对待jsonb[]
列。我会更新我的答案。